32f. That's because the force is directly proportional to the product of the masses and inversely proportional to the square of the distance. So you get 2•(1/1/4)^2=2•16=32
Answer:
the <em>revolutions per minute</em> for the 9 inch pulley is <em>10/9</em>.
Explanation:
Step 1:
The linear speed of the belt is
linear speed = circumference × revolutions per minute, that is
v = 2π r × ω
where
- r is the radius of the pulley
- ω is the revolutions per minute
Therefore, the linear speed of the 2 inch pulley is:
v₂ = (2π × 2 in) × (5 rev/min)
v₂ = 4π × (5 rev/min)
Step 2:
Compute the linear speed of the belt for the 9 inch pulley:
v₈ = (2π × 9 in) × (x rev/min)
v₈ = 18π × (x rev/min)
Step 3:
Since the linear speed is the same for both pulleys, therefore
v₂ = v₈
4π × (5 rev/min) = 18π × ω₈
ω₈ = (4π × (5 rev/min)) / 18π
<em>ω₈ = 10/9 rev/min</em>
Therefore, the <em>revolutions per minute</em> for the 8 inch pulley is <em>10/9</em>.
Explanation:
Speed: distance/time
Average speed: total distance/total time
Total distance: 400
Total time: 60
Average spead: 400/60= 6.67m/s
Answer:
F=BILsin90 when perpendicular sin90 =1 30T x50x30 so you can get 45000N
