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natulia [17]
3 years ago
15

23. Which of the following describes ionic bonds?

Chemistry
2 answers:
8_murik_8 [283]3 years ago
4 0

Answer:

b.Electrons are shared between two atoms.

STatiana [176]3 years ago
4 0
C. Electrons are transferred from one atom to another
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An atom of a certain element has 12 protons, 14 neutrons, and 2 valence electrons. What is the name of this element?
DedPeter [7]

Given :

An atom of a certain element has 12 protons, 14 neutrons, and 2 valence electrons.

To Find :

The name of this element.

Solution :

We know, element with atomic number ( number of protons ) 12 and valance electrons is Magnesium.

Now, isotope of magnesium of proton with 14 neutrons is Mg-16 .

Therefore, name of element is Mg-16 .

Hence, this is the required solution.

5 0
2 years ago
A 0.75M solution of CH3OH is prepared in 0.500 kg of water. How many moles of CH3OH are needed?
4vir4ik [10]

Answer:

We need 0.375 mol of CH3OH to prepare the solution

Explanation:

For the problem they give us the following data:

Solution concentration 0,75 M

Mass of Solvent is 0,5Kg

knowing that the density of water is 1g / mL,  we find the volume of water:

                           d = \frac{g}{mL} \\\\ V= \frac{g}{d}  = \frac{500g}{1 \frac{g}{mL} } = 500mL = 0,5 L

Now, find moles of CH_{3} OH are needed using the molarity equation:

                           M = \frac{ moles }{ V (L)} \\\\\\molesCH_{3}OH  = M . V(L) = 0,75 M . 0,5 L\\\\molesCH_{3}OH = 0,375 mol

therefore the solution is prepared using 0.5 L of H2O and 0.375 moles of CH3OH,  resulting in a concentration of 0,75M

5 0
3 years ago
10. Which term is same for one mole of O2 and one mole of ethane C2H6
melamori03 [73]

Answer:

b) Number of molecules

Explanation:

3 0
3 years ago
A sample of gas occupies 10.0 L at 240°C under a pressure of
NISA [10]

Answer: 1090°C

Explanation: According to combined gas laws

(P1 × V1) ÷ T1 = (P2 × V2) ÷ T2

where P1 = initial pressure of gas = 80.0 kPa

V1 = initial volume of gas = 10.0 L

T1 = initial temperature of gas = 240 °C = (240 + 273) K = 513 K

P2 = final pressure of gas = 107 kPa

V2 = final volume of gas = 20.0 L

T2 = final temperature of gas

Substituting the values,

(80.0 kPa × 10.0 L) ÷ (513 K) = (107 kPa × 20.0 L) ÷ T2

T2 = 513 K × (107 kPa ÷80.0 kPa) × (20.0 L ÷ 10.0 L)

T2 = 513 K × (1.3375) × (2)

T2 = 1372.275 K

T2 = (1372.275 - 273) °C

T2 = 1099 °C

8 0
3 years ago
Read 2 more answers
The measurement of grams of solute per one million grams of solution is known as
Zinaida [17]
 I think it's Molality because the moles of solute over the kilograms of solvent is equal to the molality...
5 0
3 years ago
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