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Basile [38]
3 years ago
13

The sum of the measures of angle p and angle s is 140°

Mathematics
1 answer:
Fantom [35]3 years ago
5 0

The sum of the measures of the angles of any triangle is 180 degrees. In triangle abc, angles a and b have the same measure, while the measure of angle c is 78 degrees larger than each of a and b.

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The area of a rectangle is square units. Factor this expression. Given your answer in part A, describe what you can conclude abo
Brrunno [24]

Answer:

The factored area of the rectangle=2(2w-5)

Area of a rectangle=length×width

Step-by-step explanation:

Area of rectangle is 4w - 10 square units

We have to factor the expression

Area of rectangle = 4w - 10

common factor=2

Area of rectangle = 2(2w - 5)

Thus the given expression is factored

Area of a rectangle=length × width

Area of the rectangle=2×(2w-5)

Thus, it is safe to say

The length=2 or (2w-5)

The width=(2w-5) or 2

3 0
4 years ago
Is (1, 4) a solution to this system of equations? 3x + y = 7
inysia [295]
B. Yes, (1,4) is a solution
8 0
3 years ago
Which table represents a function?​
melamori03 [73]

Answer:

Table 1

Step-by-step explanation:

In a function, you are not allowed to have two of the same x-values. Table 1 is the only one to show this.

Table 2 has two (-5)s in the x-column, Table 3 has two (-2)s, and Table 4 has two (-4)s.

5 0
4 years ago
Read 2 more answers
a circular oil slick is expanding at a rate of 2m^2/h. Find the rate at which it's diameter is expanding when it's radius is 1.5
aleksandrvk [35]

Answer:  \frac{4\pi}{3} \text{ meter per hour}

Step-by-step explanation:

The circular oil slick is expanding at a rate of  2 m^2/h

Let A be the area of the circular oil slick,

So, the changes in  A with respect to time (t),

\frac{dA}{dt} = 2

\frac{d(\pi r^2)}{dt} = 2

2\pi r\frac{dr}{dt} = 2

\frac{dr}{dt} = \frac{1}{\pi r}  

Also, the change in diameter with respect to time(t),

\frac{d}{dt} (2 r) = 2 \frac{dr}{dt}

\frac{d}{dt} (2 r) = 2 \times \frac{1}{\pi r}

\frac{d}{dt} (2 r) = \frac{2}{\pi r}

For r = 1.5 m,

\frac{d}{dt} ( 2 r)]_{r=1.5} = \frac{2}{\pi \times 1.5}=\frac{20}{\pi \times 15}=\frac{4\pi }{3}\text{ meter per hour}




7 0
3 years ago
I need help on this question can someone help.
leva [86]

Answer:

G. (8,6)

Step-by-step explanation:

remember that EF is four times the length of DE

so the distance between E and D multiplied by 4 should equal F

4 0
3 years ago
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