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Ilia_Sergeevich [38]
2 years ago
14

What is 12 times 135?

Mathematics
2 answers:
goldenfox [79]2 years ago
7 0

Answer:

1620

Step-by-step explanation:

u can time 12 by 135 or divide them

ale4655 [162]2 years ago
4 0

the answer for 135 times 12 is 1620

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Please help me with this question!
Rasek [7]

Answer:

87 packages

Step-by-step explanation:

First we need to find the volume of the cone-shaped vase.

The volume of a cone is given by:

V_cone = (1/3) * pi * radius^2 * height

With a radius of 9 cm and a height of 28 cm, we have:

V_cone = (1/3) * pi * 9^2 * 28 = 2375.044 cm3

Each package of sand is a cube with side length of 3 cm, so its volume is:

V_cube = 3^3 = 27 cm3

Now, to know how many packages the artist can use without making the vase overflow, we just need to divide the volume of the cone by the volume of the cube:

V_cone / V_cube = 2375.044 / 27 = 87.9646 packages

So we can use 87 packages (if we use 88 cubes, the vase would overflow)

5 0
3 years ago
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What is the area of a sector with measure of arc equal to 90° and radius equal to 1 foot?
pashok25 [27]

Answer:

0.7855 square feet

Step-by-step explanation:

90/360×3.142×1 squared

=0.7855

6 0
2 years ago
The movie theater sold 50 buckets of popcorn last Wednesday. 60 people watched movies that day, and 40 of those people ate popco
STALIN [3.7K]

Answer:

70

Step-by-step explanation:

60/40Ⅹ50=70

I hope this helps

3 0
2 years ago
Find the length of diagonal HJ. Round to the nearest hundredth.
Alisiya [41]

Answer:

The length of the diagonal HJ is 10.82 units

Step-by-step explanation:

* Lets revise the rule of the distance between two points

- d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}, where

 (x_{1},y_{1}) and (x_{2},y_{2}) are the two points

* Lets use this rule to find the length of the diagonal HJ

∵ The coordinates of point H are (-4 , 3)

∵ The coordinates of point J are (5 , -3)

∴ x_{1}=-4 and x_{2}=5

∴ y_{1}=3 and y_{2}=-3

- Lets find the length of the diagonal HJ by using the rule above

∴ HJ = \sqrt{(5-(-4))^{2}+(-3-3)^{2}}=\sqrt{(5+4)^{2}+(-6)^{2}}

∴ HJ = \sqrt{(9)^{2}+36}=\sqrt{81+36}=\sqrt{117}=10.81665

∴ HJ = 10.82

* The length of the diagonal HJ is 10.82 units

7 0
3 years ago
Log6 8 + log6 27 as single logarithm
Vsevolod [243]
Log[8/(36*3)] Log[2/27] Hope I really help you !
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3 years ago
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