The mass defect for the isotope thorium-234 if given mass is 234.04360 amu is 1.85864 amu.
<h3>How do we calculate atomic mass?</h3>
Atomic mass (A) of any atom will be calculated as:
A = mass of protons + mass of neutrons
In the Thorium-234:
Number of protons = 90
Number of neutrons = 144
Mass of one proton = 1.00728 amu
Mass of one neutron = 1.00866 amu
Mass of thorium-234 = 90(1.00728) + 144(1.00866)
Mass of thorium-234 = 90.6552 + 145.24704 = 235.90224 amu
Given mass of thorium-234 = 234.04360 amu
Mass defect = 235.90224 - 234.04360 = 1.85864 amu
Hence required value is 1.85864 amu.
To know more about Atomic mass (A), visit the below link:
brainly.com/question/801533
Cc stands for cm cubed (cubic centimetre).
So
6cc=6 cm^3.
Answer:
SO2
Explanation:
Dipole-Dipole exist between parmanent dipoles in a molecule. THis means that molecule must have a parmanent dipole moment in it.
Example - HCl
Hydrogen bonding is an attraction between lone pair of an electronegative element and H atom of same or different molecule. H must be covalantly attached to either F, N or O.
Example - H2O
Among the molecules given in the list only SO2 and H2O exihibits parmanent moment. As BCl3 , CBr4 and H2 are symmetric compounds.
Since, SO2 cannot exihibit H- bonding only dipole-dipole forces as its strongest intermolecular force.
Answer:
210438+28+5+8+2+2+8+30+5+8+6+8+2+5+3+82+8+9+2+8+8+5+5+5+6+9+2+56+5+6+5+-3+8+8+58+5+6+8+5+8+5+35+6+3+8+5+3+68+6+8+6+88+8+!?=8+5+55+5+5+5+5+5+5+5+5+5+2+58+0+80=0=0=00=
To find amount of atoms from mol, multiply the mole amount by Avogadro’s number
5.70x10^32 x 6.02x10^23
= 3.43x10^56 atoms
