<u><em>Answer:</em></u>
<u><em>Explanation:</em></u>
<u>Part 1: Solving for m</u>
<u>We are given that:</u>
E = mc²
To solve for m, we will need to isolate the m on one side of the equation
This means that we will simply divide both sides by c²
<u>Part 2: Solving for c</u>
<u>We are given that:</u>
E = mc²
To solve for c, we will need to isolate the m on one side of the equation
This means that first we will divide both sides by m and then take square root for both sides to get the value of c
<u>Part 3: Solving for E</u>
<u>We are given that:</u>
m = 80 and c = 0.4
<u>To get the value of E, we will simply substitute in the given equation: </u>
E = mc²
E = (80) × (0.4)²
E = 12.8 J
Hope this helps :)
3.6 x 10^-4
I am writing this sentence because the answer does not reach the 20 character limit. Thank you have nice day! :D Cx :P
Answer:
4
Explanation:
in order for the bobber to float,it must be less dense, and for the line to sink, it must be more dense.
Answer: 20) 2365 g
21) 22.39 grams.
22) 29.99 g
Explanation: 20) molarity is the no of moles of solute per unit volume.
We can calculate amount of CaCl2 required to prepare 0.1 M CaCl2 1000 ml solution.
we know that to prepare one ltr of 1 M solution of CaCl2 111 g required
Now consider x gram will require to prepare to
so that comparing above both condition
1000ml ×1M×X g=1000ml×0.1M×111g
X= 11.1 gram
X= 11.1 g of CaCl2
Hence 11.1 g of CaCl2 would be dissolved in 1.0L of a 0.100 M solution of CaCl2
21) How many moles of CaCl₂ in that solution?
;
;
.
What's the mass of that 0.20172 moles of CaCl₂?
Molar mass from a modern periodic table:
Ca- 40.078;
Cl- 35.45.
Molar mass of CaCl₂:
.
Mass of that 0.20172 moles of CaCl₂:
22) its a 3.0m solution so 1 litre of solution contains 3 moles of NaOH, 250ml of solution contains 0.25x39.9971 g/mol, so 250ml of this solution contains 0.75x39.9971=29.99g, or if you round it up 30.0g
Answer:
M = 1.04 M
Explanation:
Given data:
Molarity of solution = ?
Mass of HCl = 6.27 g
Volume of solution = 163 mL (163 mL× 1L /1000 mL = 0.163 L)
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Number of moles of HCl:
Number of moles = mass/molar mass
Number of moles = 6.27 g / 36.5 g/mol
Number of moles = 0.17 mol
Molarity:
M = 0.17 mol/ 0.163 L
M = 1.04 M
