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Alex
3 years ago
7

An upward force is applied to a 6.0–kilogram box. this force displaces the box upward by 10.00 meters. what is the work done by

the force on the box?
Physics
2 answers:
Keith_Richards [23]3 years ago
8 0
Work = fs = mgh [Ep] = 6(10)(10) = 100
Lapatulllka [165]3 years ago
3 0

Answer:

The work done by the force on the box is W = 588 J

Explanation:

The work done by the force on the box can be expressed as:

W=mg(h_{2}-h_{1})

where m is the mass of the box, g is the gravitational force g=g=9.8\frac{m}{s^{2}} and h_{2}, h_{1} are the heights of the box in at final and initial moment.

Replacing the values, you have:

W=6.0kg*9.8\frac{m}{s^{2}}*(10.00m-0.00m)

W=588\frac{kgm^{2}}{s^{2}}

that is W = 588 J

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The earth is spherical. So it's middle part is bulgjng outside. So more sunlight will be incident on the latitude near the equator. This will heat the air and it will rise up. This will cause high pressure difference and polar disturbances.

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3 years ago
Technician A says that the pushrods should be rotating while the engine is running if the camshaft and lifters are okay. Technic
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BRAINLEST TO SOMEONE WHO ACTUALLY ANSWERS AND FREE 100 POINTS TO REAL ANSWER 2. Using the average time, calculate the oscillatio
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3 years ago
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A grape is thrown straight up in the air. If it was thrown at 2 m/s, how high will it go in the air?
ser-zykov [4K]

Answer:

Answer: <u>Height</u><u> </u><u>is</u><u> </u><u>0</u><u>.</u><u>2</u><u>0</u><u>4</u><u> </u><u>m</u>

Explanation:

At the highest point, it is called the maximum height.

• From third newton's equation of motion:

{ \rm{ {v}^{2}  =  {u}^{2}  + 2gs}}

• At maximum height, v is zero

• u is initial speed

• g is -9.8 m/s²

• s is the height

{ \rm{0 {}^{2}  =  {2}^{2}   -  (2 \times 9.8 \times s)}} \\  \\ { \rm{4 = 19.6s}} \\  \\ { \rm{s = 0.204 \: m}}

4 0
2 years ago
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A rope is tied to a box and used to pull the box 2.3 m along a horizontal floor. The rope makes an angle of 30∘ with the horizon
Savatey [412]

Answer:

Answered

Explanation:

A) The work done by gravity is zero because displacement and the gravitational force are perpendicular to each other.

W= FS cosθ

θ= 90 ⇒cos90 = 0 ⇒W= 0

B) work done by tension

W= Tcosθ×S= 5cos30×2.30= 10J

C) Work done by friction force

W= f×s=1×2.30= 2.30 J

D) Work done by normal force is Zero because the displacement and the normal force are perpendicular to each other.

E) The net work done= Work done by tension in the rope - frictional work

=10-2.30= 7.7 J

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3 years ago
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