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Alex
2 years ago
7

An upward force is applied to a 6.0–kilogram box. this force displaces the box upward by 10.00 meters. what is the work done by

the force on the box?
Physics
2 answers:
Keith_Richards [23]2 years ago
8 0
Work = fs = mgh [Ep] = 6(10)(10) = 100
Lapatulllka [165]2 years ago
3 0

Answer:

The work done by the force on the box is W = 588 J

Explanation:

The work done by the force on the box can be expressed as:

W=mg(h_{2}-h_{1})

where m is the mass of the box, g is the gravitational force g=g=9.8\frac{m}{s^{2}} and h_{2}, h_{1} are the heights of the box in at final and initial moment.

Replacing the values, you have:

W=6.0kg*9.8\frac{m}{s^{2}}*(10.00m-0.00m)

W=588\frac{kgm^{2}}{s^{2}}

that is W = 588 J

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what can you say about the motion of an object if its speed time graph is a straight line parallel to the time axis ? Also draw
MaRussiya [10]

Answer:

It says about the motion and the graph of the object is stationary, basically travelling at the same speed at any time of the graph. It will never change.

Explanation:

To draw a diagram:

1. Draw an object and represent the speed as stationary and constant at any time.

5 0
2 years ago
A stone is thrown vertically upwards with a speed of 30.0 m/s.
matrenka [14]

a)

Y₀ = initial position of the stone at the time of launch = 0 m

Y = final position of stone = 20.0 meters

a = acceleration = - 9.8 m/s²

v₀ = initial speed of stone at the time of launch = 30.0 m/s

v = final speed = ?

Using the equation

v² = v₀² + 2 a (Y - Y₀)

inserting the values

v² = 30² + 2 (- 9.8) (20 - 0)

v = 22.5 m/s


b)

Y₀ = initial position of the stone at the time of launch = 0 m

Y = maximum height gained

a = acceleration = - 9.8 m/s²

v₀ = initial speed of stone at the time of launch = 30.0 m/s

v = final speed = 0 m/s

Using the equation

v² = v₀² + 2 a (Y - Y₀)

inserting the values

0² = 30² + 2 (- 9.8) (Y - 0)

Y = 46 m



6 0
3 years ago
What are two ways that machines can change the way that work is done?
algol [13]
Machines makes work easier by increasing the amount of force that is applied, and changing the direction in which the force is applied !! Hope it helped (p.s. I had this same question)
5 0
2 years ago
Read 2 more answers
Suppose a plot of inverse wavelength vs frequency has slope equal to 0.119, what is the speed of sound traveling in the tube to
strojnjashka [21]

Answer:

8.40 m/s

Explanation:

Slope of the plot is 0.119

Slope of a plot is given by the change in y direction divided by the change in x direction

Here, the y axis represents inverse wavelength and the x axis represents frequency.

f = Frequency (Hz, assumed)

v = Phase velocity (m/s, assumed)

λ = Wavelength (m, assumed)

So, slope

m=\frac{\frac{1}{\lambda}}{f}

Now,

\lambda=\frac{v}{f}\\\Rightarrow \lambda^{-1}=\frac{f}{v}

\\\Rightarrow m=\frac{\frac{f}{v}}{f}\\\Rightarrow 0.119=\frac{1}{v}\\\Rightarrow v=\frac{1}{0.119}\\\Rightarrow v=8.40\ m/s

The speed of sound travelling in the tube is 8.40 m/s

5 0
3 years ago
Can I PLEASE get some help? I REALLY need it!
soldi70 [24.7K]
The answer is C. Hope this helps.
7 0
3 years ago
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