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Alex
3 years ago
7

An upward force is applied to a 6.0–kilogram box. this force displaces the box upward by 10.00 meters. what is the work done by

the force on the box?
Physics
2 answers:
Keith_Richards [23]3 years ago
8 0
Work = fs = mgh [Ep] = 6(10)(10) = 100
Lapatulllka [165]3 years ago
3 0

Answer:

The work done by the force on the box is W = 588 J

Explanation:

The work done by the force on the box can be expressed as:

W=mg(h_{2}-h_{1})

where m is the mass of the box, g is the gravitational force g=g=9.8\frac{m}{s^{2}} and h_{2}, h_{1} are the heights of the box in at final and initial moment.

Replacing the values, you have:

W=6.0kg*9.8\frac{m}{s^{2}}*(10.00m-0.00m)

W=588\frac{kgm^{2}}{s^{2}}

that is W = 588 J

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The inner and outer surfaces of a cell membrane carry a negative and positive charge, respectively. Because of these charges, a
sertanlavr [38]

Answer:

Electric field, E = 6.36\times 10^{6}\ V/m

Explanation:

Given that,

The potential difference across the membrane, \Delta V=0.063\ V

The thickness of the membrane is, \Delta x=9.9\times 10^{-9}\ m

We need to find the magnitude of the electric field in the membrane. We know that the relation between electric field and electric potential is given by :

E=\dfrac{-\Delta V}{\Delta x}\\\\E=\dfrac{0.063\ V}{9.9\times 10^{-9}\ m}\\\\E=6.36\times 10^{6}\ V/m

So, the magnitude of the electric field in the membrane is 6.36\times 10^{6}\ V/m.

7 0
4 years ago
Two charged particles are a distance of 1.62 m from each other. One of the particles has a charge of 7.10 nc, and the other has
k0ka [10]

Answer:

A. F=107.6nN

B. Repulsive

Explanation:

According to coulombs law, the force between two charges is express as

F=(Kq1q2) /r^2

If the charges are of similar charge the force will be repulsive and if they are dislike charges, force will be attractive.

Note the constant K has a value 9*10^9

Hence for a charge q1=7.10nC=7.10*10^-9, q2=4.42*10^-9 and the distance r=1.62m

If we substitute values we have

F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)

F=(282.4×10^-9)/2.6244

F=107.6×10^-9N

F=107.6nN

B. Since the charges are both positive, the force is repulsive

8 0
3 years ago
Just a question anybody playing minècraft here?
yan [13]

Answer:

yes/nope

Explanation:

............... :)

5 0
2 years ago
Read 2 more answers
Here is more points drip students - drip king
levacccp [35]
Answer
Thanks
Explanation
4 0
3 years ago
Read 2 more answers
The weight of the heart of a cow whose weight is 1518 lbs. Answer in units of lbs.
valina [46]

Answer:

Weight of cow = 7.59 lbs

Explanation:

Given:

Weight of cow = 1518 lbs

Find:

Weight of heart of a cow

Computation:

Note: It is not given that in the mammals the weight of heart is approximately 0.5% of total body weight

Weight of heart of a cow = [Weight of cow][0.5%]

Weight of cow = [1518][0.5%]

Weight of cow = 7.59 lbs

5 0
3 years ago
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