Answer:
Electric field, E = 
Explanation:
Given that,
The potential difference across the membrane, 
The thickness of the membrane is, 
We need to find the magnitude of the electric field in the membrane. We know that the relation between electric field and electric potential is given by :

So, the magnitude of the electric field in the membrane is
.
Answer:
A. F=107.6nN
B. Repulsive
Explanation:
According to coulombs law, the force between two charges is express as
F=(Kq1q2) /r^2
If the charges are of similar charge the force will be repulsive and if they are dislike charges, force will be attractive.
Note the constant K has a value 9*10^9
Hence for a charge q1=7.10nC=7.10*10^-9, q2=4.42*10^-9 and the distance r=1.62m
If we substitute values we have
F=[(9×10^9) ×(7.10×10^-9) ×(4.42×10^-9)] /(1.62^2)
F=(282.4×10^-9)/2.6244
F=107.6×10^-9N
F=107.6nN
B. Since the charges are both positive, the force is repulsive
Answer
Thanks
Explanation
Answer:
Weight of cow = 7.59 lbs
Explanation:
Given:
Weight of cow = 1518 lbs
Find:
Weight of heart of a cow
Computation:
Note: It is not given that in the mammals the weight of heart is approximately 0.5% of total body weight
Weight of heart of a cow = [Weight of cow][0.5%]
Weight of cow = [1518][0.5%]
Weight of cow = 7.59 lbs