An upward force is applied to a 6.0–kilogram box. this force displaces the box upward by 10.00 meters. what is the work done by
2 answers:
Answer:
The work done by the force on the box is W = 588 J
Explanation:
The work done by the force on the box can be expressed as:
where m is the mass of the box, g is the gravitational force g= and
,
are the heights of the box in at final and initial moment.
Replacing the values, you have:
that is W = 588 J
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The work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.
According to Newton's second law of motion, the force applied to an object is directly proportional to the product of mass and acceleration of the object.
F = ma
The force applied to an object increases with increases in the velocity of the object.
In the given diagram, the resultant velocity of the puck is calculated as follows;
Figure a:
Figure b:
Figure c:
Thus, the work done on the Puck by the applied force from the most positive to the most negative is c, b, a respectively.
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