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Alex
3 years ago
7

An upward force is applied to a 6.0–kilogram box. this force displaces the box upward by 10.00 meters. what is the work done by

the force on the box?
Physics
2 answers:
Keith_Richards [23]3 years ago
8 0
Work = fs = mgh [Ep] = 6(10)(10) = 100
Lapatulllka [165]3 years ago
3 0

Answer:

The work done by the force on the box is W = 588 J

Explanation:

The work done by the force on the box can be expressed as:

W=mg(h_{2}-h_{1})

where m is the mass of the box, g is the gravitational force g=g=9.8\frac{m}{s^{2}} and h_{2}, h_{1} are the heights of the box in at final and initial moment.

Replacing the values, you have:

W=6.0kg*9.8\frac{m}{s^{2}}*(10.00m-0.00m)

W=588\frac{kgm^{2}}{s^{2}}

that is W = 588 J

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pentagon [3]

Explanation:

It is given that,

The Displacement x of particle moving in one dimension under the action of constant force is related to the time by equation as:

x=4t^3+3t^2-5t+2

Where,

x is in meters and t is in sec

We know that,

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v=\dfrac{dx}{dt}\\\\v=\dfrac{d(4t^3+3t^2-5t+2)}{dt}\\\\v=12t^2+6t-5

(a) i. t = 2 s

v=12(2)^2+6(2)-5=55\ m/s

At t = 4 s

v=12(4)^2+6(4)-5=211\ m/s

(b) Acceleration,

a=\dfrac{dv}{dt}\\\\a=\dfrac{d(12t^2+6t-5)}{dt}\\\\a=24t+6

Pu t = 3 s in the above equation

So,

a=24(3)+6\\\\a=78\ m/s^2

Hence, this is the required solution.

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3 years ago
Which statement is correct?
Svetach [21]
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3 years ago
What is the net force on this object f air = 400n (up) fgrav=600n (down)
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5 0
3 years ago
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Starting from rest, a car undergoes a constant acceleration of 6 m/s^2. How far will the car travel in the two seconds?
oksano4ka [1.4K]

If time is specified, the distance may be estimated in constant acceleration using the formula: X=(at2)/2 if the beginning velocity is 0. (A automobile begins from a stop...) As a result, X=(6*10*10)/2=600/2 = 300 m.

4 0
2 years ago
What is the amount of work done when a force of 10N moves a 20kg mass of 8 meters?
Nataly_w [17]

Yo sup??

we should know that

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W=F.s

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therefore

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=80 N

Hope this helps.

3 0
3 years ago
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