An upward force is applied to a 6.0–kilogram box. this force displaces the box upward by 10.00 meters. what is the work done by
2 answers:
Answer:
The work done by the force on the box is W = 588 J
Explanation:
The work done by the force on the box can be expressed as:
where m is the mass of the box, g is the gravitational force g= and
,
are the heights of the box in at final and initial moment.
Replacing the values, you have:
that is W = 588 J
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Answer:
The hollow cylinder rolled up the inclined plane by 1.91 m
Explanation:
From the principle of conservation of mechanical energy, total kinetic energy = total potential energy
The total energy at the bottom of the inclined plane = total energy at the top of the inclined plane.
moment of inertia, I, of a hollow cylinder = ¹/₂mr²
substitute for I in the equation above;
given;
v₁ = 5.0 m/s
vf = 0
g = 9.8 m/s²
Therefore, the hollow cylinder rolled up the inclined plane by 1.91 m