An upward force is applied to a 6.0–kilogram box. this force displaces the box upward by 10.00 meters. what is the work done by
2 answers:
Answer:
The work done by the force on the box is W = 588 J
Explanation:
The work done by the force on the box can be expressed as:
where m is the mass of the box, g is the gravitational force g= and
,
are the heights of the box in at final and initial moment.
Replacing the values, you have:
that is W = 588 J
You might be interested in
Answer:
12 cm
Explanation:
We shall use Lens makers formula here which is as follows
Put μ = 1.5 , R₁ = 10 cm ,R₂ = - 15 cm ( according to sign convention )
= .5 x ( 15 + 10 ) / 15 x 10
=
F = 12 cm
Answer:
angular frequency of the table must be same as the frequency of the projection of the gum on the wall
Explanation:
Since we know that the projection on the wall is the vertical component of the position of the gum on the rotating table
So here we will say
so the angle made by the radius vector depends on the angular frequency of the disc by which it is rotating
So we can say
so here we can say
so here we can say that
angular frequency of the table must be same as the frequency of the projection of the gum on the wall