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sattari [20]
2 years ago
5

Estimate material for a project - We need to make 75 plaques that are 12 inches wide and 15 inches long. The material available

is maple and walnut. Walnut is 10 inches wide by 8 feet long, Maple is 8 inches wide by 8 feet long. How many boards of each do we need?
Engineering
1 answer:
kozerog [31]2 years ago
5 0

Answer:

Image result for Estimate material for a project - We need to make 75 plaques that are 12 inches wide and 15 inches long. The material available is maple and walnut. Walnut is 10 inches wide by 8 feet long, Maple is 8 inches wide by 8 feet long. How many boards of each do we need?

You can measure board feet by multiplying length x width x thickness in inches, and then dividing by 144. If ordering a large amount by board feet, just multiply the total board feet needed by the price per board foot for the total cost. i think it help you

Explanation:

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Which of the following identifies one factor that causes conventional tillage to actually be good for the environment?
Brums [2.3K]

Answer:

Farmers who use conventional tillage use compost more than other farmers.

Explanation:

Convectional tillage is good to the environment because it attains the following;

  • It increases porosity of the soil
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  • It is an effective way to incorporate manure and break sod fields
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8 0
3 years ago
Calculate the angle of banking on a bend of 100m radius so that vehicles can travel round the bend at 50km/hr without side thrus
saw5 [17]

Answer:

11.125°

Explanation:

Given:

Radius of bend, R = 100 m

Speed around the bend = 50 Km/hr = \frac{5}{18}\times50 = 13.89 m/s

Now,

We have the relation

\tan\theta=\frac{v^2}{gR}

where,

θ = angle of banking

g is the acceleration due to gravity

on substituting the respective values, we get

\tan\theta=\frac{13.89^2}{9.81\times100}

or

\tan\theta=0.1966

or

θ = 11.125°

3 0
3 years ago
A cylindrical specimen of some metal alloy having an elastic modulus of 106 GPa and an original cross-sectional diameter of 3.9
kiruha [24]

Answer:

L= 312.75 mm

Explanation:

given data

elastic modulus E = 106 GPa

cross-sectional diameter d = 3.9 mm

tensile load F = 1660 N

maximum allowable elongation ΔL = 0.41 mm

to find out

maximum length of the specimen before deformation

solution

we will apply here allowable elongation equation that is express as

ΔL =     \dfrac{FL}{AE}     ....................1

put here value and we get L

L   =    \dfrac{0.41\times 10^{-3}\times \dfrac{\pi}{4}\times (3.9\times 10^{-3})^2\times 106\times 10^9}{1660}

solve it we get

L = 0.312752 m

L= 312.75 mm

8 0
4 years ago
dentify a semiconducting material and provide the value of its band gap) that could be used in: (a) (1 point) red LED (b) (1 poi
OLga [1]

Answer:

(a) Aluminum Indium Gallium Phosphide (AlInGaP). Band gap = 1.81eV  ≈ 2eV

(b) Gallium Nitride (GaN). Band Gap = 3.4eV

(c) Aluminium Gallium Arsenide (AlGaA). Band Gap = 1.42eV ≈ 2.16eV

(d) Zinc Selenide (ZnSe). Band Gap = 2.82eV

(e) Gallium Phosphide (GaP). Band Gap = 2.24eV

Explanation:

LED's are semi-conducting materials that convert electrical energy to light energy. The light color emitted from the LED depends on the semi-conducting material and other compositions.

The band gap of the semi-conductor determines its wavelength. High band gap semi-conductors emit lower wavelengths which means greater power(UV semi-conducting macterials fall under this category).

5 0
3 years ago
we wish to send at a rate of 10Mbits/s over a passband channel. Assuming that an excess bandwidth of 50% is used, how much bandw
gayaneshka [121]

Answer:

QPSK: 7.5 MHz

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Explanation:

See attached picture.

6 0
3 years ago
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