Question

A cylindrical specimen of some metal alloy having an elastic modulus of 106 GPa and an original cross-sectional diameter of 3.9 mm will experience only elastic deformation when a tensile load of 1660 N is applied. Calculate the maximum length of the specimen before deformation if the maximum allowable elongation is 0.41 mm.

Answer 1

Answer:

L= 312.75 mm

Explanation:

given data

elastic modulus E = 106 GPa

cross-sectional diameter d = 3.9 mm

tensile load F = 1660 N

maximum allowable elongation ΔL = 0.41 mm

to find out

maximum length of the specimen before deformation

solution

we will apply here allowable elongation equation that is express as

ΔL =     $\dfrac{FL}{AE}$     ....................1

put here value and we get L

L   =    $\dfrac{0.41\times 10^{-3}\times \dfrac{\pi}{4}\times (3.9\times 10^{-3})^2\times 106\times 10^9}{1660}$

solve it we get

L = 0.312752 m

L= 312.75 mm