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Marta_Voda [28]
3 years ago
15

Hola! necesito las respuestas de "fuerzas"

Physics
1 answer:
Alexus [3.1K]3 years ago
5 0
I need help on this to I have to get the answer fast
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Which of the following statements CANNOT be supported by Kepler's laws of planetary motion?
horsena [70]

Answer:

B) A planet's speed as it moves around the sun will not be the same in six months.

Explanation:

A planet's speed as it moves around the sun will not be the same in six months, is a  statement that CANNOT be supported by Kepler's laws of planetary motion.

8 0
3 years ago
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PLEASE HELP ME!!!
klasskru [66]

1.velocity and acceleration

2.

3.inertia

4.

5.speed

4 0
3 years ago
Normally light waves move in all different directions. When light becomes P________, all of the electric fields in the waves mov
Aloiza [94]

Answer:im so sorry i cant find anything either ask your teacher for some help is the best thing i can do

4 0
2 years ago
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At this rate, how long would it take for two continents 3500 kilometers apart to collide?
meriva

<span>Given:

3,500 kilometers

Find:</span>

 

Years for two continents to collide = ?

 

<span>Solution:

We know that </span>typical motions of one plate relative to another are 1 centimeter per year.

So first, we convert 3,500 km to cm.<span>
</span><span>

</span>

The solution would be like this for this specific problem:

 

1 km = 100,000 cm

3,500 km x 100,000 = 350,000,000 cm

Since we know that 1 cm = 1 year, then that means 350,000,000 cm is equivalent to 350,000,000 years.

 

Therefore, it would take 350 million years for two continents that are 3500 kilometers apart to collide.

<span>
To add, </span>a phenomenon of the plate tectonics of Earth that occurs at convergent boundaries is called the continental collision.

5 0
3 years ago
A 12.0 μF capacitor is charged to a potential of 50.0 V and then discharged through a 265 Ω resistor. A)How long does the capaci
larisa [96]

(a) The time for the capacitor to loose half its charge is 2.2 ms.

(b) The time for the capacitor to loose half its energy is 1.59 ms.

<h3>Time taken to loose half of its charge</h3>

q(t) = q₀e-^(t/RC)

q(t)/q₀ = e-^(t/RC)

0.5q₀/q₀ = e-^(t/RC)

0.5 = e-^(t/RC)

1/2 =  e-^(t/RC)

t/RC = ln(2)

t = RC x ln(2)

t = (12 x 10⁻⁶ x 265) x ln(2)

t = 2.2 x 10⁻³ s

t = 2.2 ms

<h3>Time taken to loose half of its stored energy</h3>

U(t) = Ue-^(t/RC)

U = ¹/₂Q²/C

(Ue-^(t/RC))²/2C = Q₀²/2Ce

e^(2t/RC) = e

2t/RC = 1

t = RC/2

t = (265 x 12 x 10⁻⁶)/2

t = 1.59 x 10⁻³ s

t = 1.59 ms

Thus, the time for the capacitor to loose half its charge is 2.2 ms and the time for the capacitor to loose half its energy is 1.59 ms.

Learn more about energy stored in capacitor here: brainly.com/question/14811408

#SPJ1

6 0
2 years ago
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