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3 years ago

Rocks in mountains can be weathered by breaking them apart. How can they be eroded?

Engineering

1 answer:

Ksju [112]3 years ago

5 0

Answer: If you look up its definition of eroded it'll tell you the answer should be B

Explanation:

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What are materials engineers trying to discover when they study different materials?

coldgirl [10]

What do materials science and engineering graduates do?
Almost two-thirds of materials science graduates are in employment six months after graduation.

The skills developed during a materials science degree allow graduates enter a range of sectors, including working as engineering professionals and in design and marketing roles.

Destination Percentage
Employed 60.4
Further study 24.5
Working and studying 5.1
Unemployed 4
Other 6.1
Graduate destinations for materials science and engineering
Type of work Percentage
Engineering and building 23.9
Marketing, PR and sales 11.9
Business, HR and financial 11.7
Technicians and other professionals 10
Other 42.5

5 0

3 years ago

Read 2 more answers

Vehicles begin arriving at an amusement park 1 hour before the park opens, at a rale of four vehicles per minute. The gale to th

Alina [70]

Answer:

a) ≈ 30 mins

b) 8 vpm

Explanation:

<u>a) Determine how long after the first vehicle arrival will the queue dissipate</u>

The time after the arrival of the first vehicle for the queue to dissipate

= 29.9 mins ≈ 30 mins

<u>b) Determine the average service rate at the parking lot gate </u>

U = A / t

where : A = 240 vehicles , t = 30

U = 240 / 30 = 8 Vpm

attached below is a detailed solution of the given problems above

3 0

3 years ago

A vehicle of 1 200 kg is moving at a speed of 40 km/h on an incline of 1 in 50. The total constant rolling and wind resistance i

Readme [11.4K]

Answer:11.602 KW

Explanation:

mass of vehicle $\left ( m\right )=1200 kg$

speed=40Km/h

Resistance=600 N

$\eta =80%$

Gear ratio $\left ( G\right )=4:1$

$D_{effective}=500mm$

Net force to overcome by engine is

F=Resistance + sin component of weight

F=600+ $mgsin\theta$

Where $tan\theta =[tex]\frac{1}{50}$

$\theta =1.1457^{\circ}$

$F=600+1200\times 9.81\times sin\left ( 1.1457\right )$

F=600+235.38=835.38 N

power= $F.v=835.38\frac{100}{9}$

Engine Power= $\frac{835.\frac{100}{9}}{\eta }$ =11.602 KW

4 0

4 years ago

Discuss typical advantages and disadvantages of an irrigation system?

trapecia [35]

Advantages include low costs and minimal labor.Water stays in the root zone, and foliage stays dry. Drawbacks to surface irrigation include potential overwatering and wasteful runoff.

4 0

3 years ago

Select the correct answer.

ArbitrLikvidat [17]

......The answer is D

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3 years ago