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3 years ago

Discuss typical advantages and disadvantages of an irrigation system?

1 answer:

4 0

Advantages include low costs and minimal labor.Water stays in the root zone, and foliage stays dry. Drawbacks to surface irrigation include potential overwatering and wasteful runoff.

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The theoretical maximum specific gravity of a mix at 5.0% binder content is 2.495. Using a binder specific gravity of 1.0, find

PSYCHO15rus [73]

Answer:

The theoretical maximum specific gravity at 6.5% binder content is 2.44.

Explanation:

Given the specific gravity at 5.0 % binder content 2.495

Therefore

95 % mix + 5 % binder gives S.G. = 2.495

Where the binder is S.G. = 1, Therefore

Per 100 mass unit we have (Mx + 5)/(Vx + 5) = 2.495

(95 +5)/(Vx +5) = 2.495

2.495 × (Vx + 5) = 100

Vx =35.08 to 95

Or density of mix = Mx/Vx = 95/35.08 = 2.7081

Therefore when we have 6.5 % binder content, we get

Per 100 mass unit

93.5 Mass unit of Mx has a volume of

Mass/Density = 93.5/2.7081 = 34.526 volume units

Therefore we have

At 6.5 % binder content.

(100 mass unit)/(34.526 + 6.5) = 2.44

The theoretical maximum specific gravity at 6.5% binder content = 2.44.

3 0

3 years ago

Universal Containers (UC) has a requirement to expose a web service to their business partners. The web service will be used to

ivanzaharov [21]

Answer:

"- Set the Orders object's sharing settings to Private in the Org-Wide Defaults

_Provide each partner with their own Salesforce login set to API Enabled on the profile

-Develop a custom Apex web service using the "With Sharing" keyword"

Explanation:

Universal Containers (UC) has a requirement to expose a web service to their business partners. The web service will be used to allow each business partner to query UC's Salesforce instance to retrieve the status of orders. The business partner should only be allowed access to orders for which the business partner is the fulfillment vendor. The Architect does not want the business partners to utilize the standard APIs and would prefer a custom API be developed. Which three design elements should the Architect consider in order to ensure the data security of the solution?

A. Query the Orders object with Dynamic SOQL based upon the fulfillment ID.

B. Set the Orders object's sharing settings to Private in the Org-Wide Defaults

C. Provide each partner with their own Salesforce login set to API Enabled on the profile.

D. Develop a custom Apex web service with a fulfillment ID input attribute

E. Develop a custom Apex web service using the "With Sharing" keyword.

The above should be a follow up option to the question

The Architect should consider the following design

"- Set the Orders object's sharing settings to Private in the Org-Wide Defaults

_Provide each partner with their own Salesforce login set to API Enabled on the profile

-Develop a custom Apex web service using the "With Sharing" keyword"

There is need for some sharing rule between the architect and the user

3 0

3 years ago

There are two ingredients (A and B) that will be mixed in the reactor tank. Wait for READY signal to be on (when on, it signifie

Svet_ta [14]

Answer:

Find attached of the designed PLC

Explanation:

See the attached file for the explanation.

5 0

3 years ago

When cutting a full 4' x 8' sheet of plywood into a strips 12" wide what is the best tool to use?

stepladder [879]

A saw pls mark me braliest heheheheh also yeah use a saw

8 0

3 years ago

P1.30 shows a gas contained in a vertical piston– cylinder assembly. A vertical shaft whose cross-sectional area is 0.8 cm2 is a

iogann1982 [59]

Answer:

1.737 kJ

Explanation:

Thinking process:

Step 1

Data:

Area of the shaft = 0.8 cm²

Combined mass of shaft and piston = (24.5 + 0.5) kg

= 25 kg

Piston diameter = 0.1 m

External atmospheric pressure = 1 bar = 101.3 kPa

Pressure inside the gas cylinder = 3 bar = 3 × 101.3 kPa

g = 9.81 m/s²

Step 2

Draw a free body diagram

Step 3: calculations

area of the piston = 0.0314 m²

Change in the elevation of the piston, $\deltaz$

$\delta$ z = $\frac{PE}{mg}$

= $\frac{0.2*10x^{3} }{25*9.81}$

= 0.82 m

Next, we evaluate the work done by the shaft:

$W_{s} = F_{s} Z$

= (1668) ( 0.082)

= 1. 37 kJ

Net area for work done = A (piston) - Area of shaft

= $\pi*(0.1)^{2} - 0.8 cm^{2}$

= 77.7 cm²

= 0.007774 m²

Work done in overcoming atmospheric pressure:

Wₐ = PAZ

=101.3 kPa * 0.007774 * 0.82

= 0.637 kJ

total work = work done by shaft + work to overcome atmospheric pressure = 0.367 + 1.37

= 1.737 kJ Ans

6 0

3 years ago