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Anastasy [175]
3 years ago
8

The Mamestra brassicae a moth is primarily known as a pest that is responsible for severe crop damage on a wide variety of plant

species. Because there are limited means of chemically controlling the species, the use of wasp species that parasitize the eggs is used to control the reproduction and hence presence of these moths in agricultural crops. At a farm where a wasp species was introduced the eggs of the moths where collected and examined to determine if the wasps had successfully parasitized the eggs of the moths. Of 100 eggs collected 64 were determined to have been taken over by the wasps. Determine the 95% confidence interval for the true proportion moth eggs parasitized by the wasps.
Engineering
1 answer:
expeople1 [14]3 years ago
3 0

The 95% confidence interval for the true proportion moth eggs parasitized by the wasps is;

CI = (0.5459, 0.7341)

We are given;

Sample size; n = 100

Number of successes in the sample; x = 64

Now, formula for estimated proportion of success is; p = x/n

p = 64/100

p = 0.64

Formula for confidence interval of proportions is;

CI = p ± z√(p(1 - p)/n)

Where z is the critical value at the confidence level.

From tables, at 95% CL, critical value z = 1.96

Thus;

CI = 0.64 ± 1.96√(0.64(1 - 0.64)/100)

CI = 0.64 ± 0.0941

Thus;

CI = (0.64 - 0.0941), (0.64 + 0.0941)

CI = (0.5459, 0.7341)

Read more about confidence interval at;brainly.com/question/17042789

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One problem with organic equations is that we tend to focus on what is happening to onemolecule at a time, we forget that there
stellarik [79]

Answer:

1 2 200 000 000 000 000 000 000 (20 zeros) molecules

Explanation:

Molar mass of 1-butanol = 74.121 g/mol

number of moles = mass given / molar mass

where mass given = 1.5 g

number of mole = 1.5 g / (74.121g/mol ) = 0.0202 moles

number of moles = number of molecules / Avogadro's constant

where Avogadro's = 6.022 × 10²³ mol⁻¹

number of moles = 6.022 × 10²³ × 0.0202 moles = 1 2 200 000 000 000 000 000 000 (20 zeros) molecules

3 0
3 years ago
What is the step in which you are testing your hypothesis ​
jonny [76]

Answer:

Step 1: State your null and alternate hypothesis. ...

Step 2: Collect data. ...

Step 3: Perform a statistical test. ...

Step 4: Decide whether the null hypothesis is supported or refuted. ...

Step 5: Present your findings.

8 0
3 years ago
What is the primary difference between the process of lost-wax casting as practiced in ancient times and that same process today
Bad White [126]

Answer:

Today, multiples can be created from the process. high-relief projects boldly from the background, and elements of high-relief may be in the round, unattached to the background.

5 0
3 years ago
Air modeled as an ideal gas enters a combustion chamber at 20 lbf/in.2
motikmotik

Answer:

The answer is "112.97 \ \frac{ft}{s}"

Explanation:

Air flowing into thep_1 = 20 \ \frac{lbf}{in^2}

Flow rate of the mass m  = 230.556 \frac{lbm}{s}

inlet temperature T_1 = 700^{\circ} F

PipelineA= 5 \times 4 \ ft

Its air is modelled as an ideal gas Apply the ideum gas rule to the air to calcule the basic volume v:

\to \bar{R} = 1545 \ ft \frac{lbf}{lbmol ^{\circ} R}\\\\ \to M= 28.97 \frac{lb}{\bmol}\\\\ \to pv=RT \\\\\to v= \frac{\frac{\bar{R}}{M}T}{p}

      = \frac{\frac{1545}{28.97}(70^{\circ}F+459.67)}{20} \times \frac{1}{144}\\\\=9.8 \frac{ft3}{lb}

V= \frac{mv}{A}

   = \frac{230.556 \frac{lbm}{s} \times 9.8 \frac{ft^3}{lb}}{5 \times 4 \ ft^2}\\\\= 112.97 \frac{ft}{s}

8 0
3 years ago
1. A first class lever in statistics equilibrium has a 75 Ib resistance force and a 20 Ib effort force. The lever's effort force
Mashutka [201]

Answer:

1. 3.75

2. 1.39 ft

Explanation:

The mechanical advantage is the ratio of the resistance force to the effort force.

MA = 75 lb / 20 lb

MA = 3.75

The sum of the torques about the fulcrum equals zero.

∑τ = Iα

(20 lb) (5.2 ft) − (75 lb) x = 0

x = 1.39 ft

Round as needed.

8 0
3 years ago
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