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balandron [24]
4 years ago
6

Sometimes reactions to prices in oligopolistic markets can result in _________

Chemistry
1 answer:
STatiana [176]4 years ago
7 0

Answer:

a price war

Explanation:

An Oligopoly is when a small group of two or more companies dominates a market. Oligopoly firms may consent to market collusion, and create barriers to new commerce entry. If the businesses do not, they will probably be forced to lower their prices and open the market to new and smaller companies.

It is the type of competition between the company selling the similar type of product , or rival companies who tries to reduce the price of the product strategizing in a way to apprehend the wider area of the market , is known as a price war .

In the event one of the firms forming the oligopoly decides to lower prices, a price war occurs breaking the balance of the oligopoly and destabilizing the equilibrium of demand and supply in that market.

Reduction of the price of any goods or commodity is considered to be one of the best method to increase its market share ,because as soon as the price of any good decreases , the sales automatically increases , as the consumers are always in search of some discounts and good deals .

price war -

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I2(g) + Cl2(g)2ICl(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.62 mol
galina1969 [7]

Answer:

The change in entropy of the surrounding is -146.11 J/K.

Explanation:

Enthalpy of formation of iodine gas = \Delta H_f_{(I_2)}=62.438 kJ/mol

Enthalpy of formation of chlorine gas = \Delta H_f_{(Cl_2)}=0 kJ/mol

Enthalpy of formation of ICl gas = \Delta H_f_{(ICl)}=17.78 kJ/mol

The equation used to calculate enthalpy change is of a reaction is:  

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

I_2(g)+Cl_2(g)\rightarrow 2ICl(g),\Delta H_{rxn}=?

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]

=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol

Enthaply change when 1.62 moles of iodine gas recast:

\Delta H= \Delta H_{rxn}\times 1.62 mol=(-26.878 kJ/mol)\times 1.62 mol=-43.542 kJ

Entropy of the surrounding = \Delta S^o_{surr}=\frac{\Delta H}{T}

=\frac{-43.542 kJ}{298 K}=\frac{-43,542 J}{298 K}=-146.11 J/K

1 kJ = 1000 J

The change in entropy of the surrounding is -146.11 J/K.

4 0
3 years ago
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