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AfilCa [17]
3 years ago
12

Which two factors determine the amount of work done?

Physics
2 answers:
nignag [31]3 years ago
5 0
Distance and force.
You need to know how much force was needed and how far it went to calculate how much work was done. The answer is C.
dimaraw [331]3 years ago
5 0
<h3><u>Answer;</u></h3>

C.distance and force

<h3><u>Explanation;</u></h3>
  • Work done is defined as the product of force and distance. Work is measured in Joules, like energy.
  • <em><u>Work is done when a given  force that is applied to an object moves that object from its initial position to another position. The work is calculated by multiplying the force by the distance of movement by an object </u></em>

Work done = Force × Distance

  • Therefore, <em><u>the work done on a given object depends on the force applied and the distance moved by the object.</u></em>
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What is air pressure?
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9. (02.04 LC)
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7 0
3 years ago
A small block with a mass of 0.0600 kg is attached to a cord passing through a hole in a frictionless, horizontal surface (Figur
pogonyaev

Answer with Explanation:

We are given that mass of block=0.0600 kg

Initial speed of block=0.63 m/s

Distance of block  from the hole when the block is revolved=0.47 m

Final speed=3.29 m/s

Distance of block  from the hole when the block is revolved=9\times 10^{-2}m

a.We have to find the tension in the cord in the original situation when the block has speed =v_0=0.63 m/s

T=\frac{mv^2}{r}

Because tension is equal to centripetal force

Substitute the values

T=\frac{0.06\times (0.63)^2}{0.47}=0.05 N

b.v=3.29 m/s

T=\frac{mv^2}{r}=\frac{0.06\times (3.29)^2}{0.09}=7.2 N

c.Work don=Final K.E-Initial K.E

W=\frac{1}{2}m(v^2-v^2_0)

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W=0.31 J

4 0
3 years ago
Read 2 more answers
an engine has been design to work between source and the sink at temperature 177 degree Celsius and 27 degree Celsius respective
irina [24]

<u>Given data</u>

Source temperature (T₁) = 177°C = 177+273 = 450 K

Sink temperature (T₂) = 27°C = 27+273 = 300 K

Energy input (Q₁) = 3600 J ,

Work done = ?

                We know that, efficiency (η) = Net work done ÷ Heat supplied

                                                           η =   W ÷ Q₁  

                                                           W = η × Q₁

               First determine the efficiency ( η ) = ?

                                Also, we know that ( η ) = (T₁ - T₂) ÷ (T₁)

                                                                        = 33.3% = 0.333

               Now, Work done is W = η × Q₁

                                                    = 0.33 × 3600

                                                 <em>  W = 1188 J</em>

<em>Work done by the engine is 1188 J</em>

4 0
3 years ago
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