1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lukranit [14]
4 years ago
15

A 5 kg object near Earth's surface is released from rest such that it falls a distance of 10 m. After the object falls 10 m, it

has a speed of 12 m/s. Which of the following correctly identifies whether the object-Earth system is open or closed and describes the net external force?
A. The system is closed, and the net external force is zero.
B. The system is open, and the net external force is zero.
C. The system is closed, and the net external force is nonzero.
D. The system is open, and the net external force is nonzero.
Physics
1 answer:
makkiz [27]4 years ago
4 0

Answer:D

Explanation:

Given

mass of object m=5 kg

Distance traveled h=10 m

velocity acquired v=12 m/s

conserving Energy at the moment when object start falling and when it gains 12 m/s velocity

Initial Energy=mgh=5\times 9.8\times 10=490 J

Final Energy=\frac{1}{2}mv^2+W_{f}

=\frac{1}{2}\cdot 5\cdot 12^2+W_{f}

where W_{f} is friction work if any

490=360+W_{f}

W_{f}=130 J

Since Friction is Present therefore it is a case of Open system and net external Force is zero

An open system is a system where exchange of energy and mass is allowed and Friction is acting on the object shows that system is Open .

You might be interested in
A 150 kg object takes 90 seconds to travel a 2500 meter straight path. It begins the trip traveling 120 meters per second and de
Nana76 [90]

The acceleration is -1.111 m/s²

Explanation:

In this case acceleration is calculated as change in velocity divided by time.

Change in velocity is 20m/s-120 m/s = -100 m/s

Time is 1.5 minutes------change it to seconds by multiplying 1.5 by 60 seconds

Acceleration will be : -100 m/s / (1.5*60) = -1.111 m/s²

Learn More

To calculate acceleration :brainly.com/question/856414

Keywords : object, travel, straight path, velocity, decelerate, acceleration

#LearnwithBrainly

3 0
4 years ago
Which of the following electromagnets is the strongest? Why?​
Digiron [165]

Answer:

Bitter Magnet inside a superconducting magnet

Explanation:

Since there are no options available, generally, the electromagnet that is considered the strongest is the Bitter Magnet inside a superconducting magnet.

This electromagnet produces 45 Tesla units which is a result of bitter magnet producing 33.5 Tesla and the superconducting coil produces the additional 11.5 Tesla.

Hence, justifying that the greater the current in the coil the stronger the electromagnet. ​

4 0
4 years ago
An unknown mass is on a flat frictionless surface and a 2 kg object is attached to it with a string going over pulleyt mounted t
Lynna [10]

Answer:

Explanation:

F=ma

F in this case is the gravity acting on the 2kg object. Acceleration of gravity is 9.8 m/s^2. SF=ma, so

F = 2kg*(9.8 m/s^2) = 19.6 N

Now use this force to determine the mass of the object on the table:

F=ma

19.6 N (1N=kg*m/s^2) = m*(1.8 m/s^2)

m = 10.89 kg

3 0
3 years ago
An imaginary line perpendicular to a reflecting surface is called _________.
n200080 [17]
<span>An imaginary line perpendicular to a reflecting surface is called "a normal" (principle line)

So, Your Answer would be Option B

Hope this helps!</span>
5 0
3 years ago
Read 2 more answers
A portable basketball set has a base and a post arrangement. The post arrangement consists of a post, backboard, hoop and net. T
Ray Of Light [21]

The rotational equilibrium condition allows finding the response to the minimum force of the wind and what happens when changing the water for sand, in the system

  a) The minimum force of the wind that turns the system is Fw = 17.64 N

  b) The system resists much greater forces because the base has more mass

 Newton's Second Law can be applied to rotational motion in this case when the angular acceleration is zero we have the special case of rotational equilibrium

               Σ τ = 0

Where τ is the torque  

The reference system is a coordinate system with respect to which the torques are measured, in this case we will fix the system at the turning point, the junction of the base and the pole, we will assume that the counterclockwise rotations are positive.

For the torque the distance used is the perpendicular distance from the direction of the force to the axis of rotation, let's find this distance for each force

Wind force

         cos 15 = \frac{y_w}{2.35}

         y_w = 2.35 cos 15

Post Weight

        sin 15 = \frac{x_p}{2.00}

         xp = 2.0 sin 15

Base weight

         cos (90-15) = \frac{x_b}{0.25}

         xB = 0.25 cos 75

Let's substitute in the rotational equilibrium equation

     

          F_w \ y_w  + W_p \ x_p - W_b \ x_b = 0

a) To calculate the minimum wind force we substitute the given values

They indicate the weight of the post is W_p = 26.0 N and the weight of the base with water is W_b = 810 N

     F_w = \frac{W_b \ x_b - W_p \ x_p }{y_w}

     F_w = \frac{W_b \ 0.25 cos75 \ - W_p \ 2 sin 15}{2.35 cos 15}

       

Let's  calculate

     F_w = \frac{810 \ 0.25 \ cos75 \ - 26.0 \ 2 \ sin 15}{2.35 cos15}\\F_w = \frac{52.41 - 10.30}{2.3699}

     F_w = 17.64 N

b) The water is exchanged for sand.

In this case, as the density of the sand is greater than that of the water, the base will have more weight, so it will resist stronger winds before turning over.

Using the rotational equilibrium condition we can find the response to the minimum force of the wind and what happens when changing the water for sand,

  a) the minimum force of the wind that turns the system is Fw = 17.64 N

  b) the system resists much greater forces because the base has more mass

Learn more  here: brainly.com/question/7031958

3 0
3 years ago
Other questions:
  • What radius should the satellite move at in its orbit? (measured frrom the center of mars.)?
    9·1 answer
  • Two 6.7 kg bodies, A and B, collide. The velocities before the collision are and . After the collision, . What are (a) the x-com
    10·1 answer
  • A person who is 180 cm tall and weighs 750 newtons is driving a car at a speed of 90 kilometers per hour over a distance of 80 k
    15·1 answer
  • Is this true or false?
    13·2 answers
  • Explain why heating destroys the magnetism in a permanent magnet?​
    8·2 answers
  • What information is represented by the slope of a graph of displacement versus time (displacement-time graph)?​
    9·1 answer
  • Potential diffetence​
    10·1 answer
  • Help please 10 pts and quick!!
    15·1 answer
  • A stone is dropped from a cliff 64 feet above the ground. Answer the following, using -32 ft/sec2 as the acceleration due to gra
    5·1 answer
  • 9) A string exerts a force of 58 N on a box at an angle of 34 degrees from the horizontal. The box has a mass of 4 kg
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!