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Paladinen [302]

3 years ago

6

Balance the folowing equation. S + 02 ws SO:

1 answer:

Rzqust [24]3 years ago

6 0

Answer:

s+o2=so2

Explanation:

i hope it will help u

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If starch, glucose and NaCl are soaked in the dialysis tubing , will there be a difference between the beginning and after 15min

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<span>Yes. If you put solutions containing the same concentration table salt, glucose and starch in different bags and place the bags in water (i.e., 0M) solution, then the bag with salt will contain more water after 15 minutes than the bag with glucose, which will contain more than the bag with starch.</span>

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3 years ago

What element is in group 13, period 4

Ludmilka [50]

Answer:

Gallium

Explanation:

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3 years ago

Read 2 more answers

Define duplet and octet??

Bogdan [553]

Answer:
duplet-A set of two things or people
Octet-A group of 8 things or people

5 0

3 years ago

A sample of an ideal gas at 1.00 atm and a volume of 1.84 L was placed in a weighted balloon and dropped into the ocean. As the

Inessa05 [86]

Answer:

0.0613 L

Explanation:

Given data

Initial pressure (P₁): 1.00 atm

Initial volume (V₁): 1.84 L

Final pressure (P₂): 30.0 atm

Final volume (V₂): ?

Since we are dealing with an ideal gas, we can calculate the final volume using Boyle's law.

P₁ × V₁ = P₂ × V₂

V₂ = P₁ × V₁ / P₂

V₂ = 1.00 atm × 1.84 L / 30.0 atm

V₂ = 0.0613 L

6 0

3 years ago

The temperature of 15.71 grams of gold rises from 32°C to 1,064°C, and then the gold melts completely. If gold’s specific heat i

antoniya [11.8K]

Answer:Total energy gained by 15.71 g is 3090.6471 joules

Explanation:

Given:

Q = heat gained by the 15.71 gram mass of gold

$Q=mc\Delta T +m\Delta H_{fusion}$

$\Delta T=(T_{final}-T_{initial})=(1064^oC-32^oC)=1032^oC$

c = specific heat capacity of gold = 0.1291 $joules/gram^oC$

m = mass of gold =15.71 g

$Q=15.71 g\times 0.1291 joules/gram^oC (1032^oC) +15.71 g\times 63.5 Joules/gram$

Heat gained by gold = $2093.0621 Joules + 997.585 Joules$

=3090.6471 joules

6 0

3 years ago