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Naddik [55]
3 years ago
11

What energy transformations take place when you turn on a fan?

Physics
1 answer:
Snezhnost [94]3 years ago
8 0

Answer:

Electrical energy to kinetic energy

Explanation:

The transformation that occurs when turning on a fan is electrical energy to kinetic energy.

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If the only force exerted on a star far from the center of the Galaxy (r = 7.40 ✕ 1020 m) is the gravitational force exerted by
lina2011 [118]

Answer:

The value is  v = 1.309*10^{5}\ m/s

Explanation:

The radius is r = 7.40 *10^{20} \  m

The mass of the ordinary matter is M_{rod} =  1.90 *10^{41}\  kg

Generally the speed of the star is mathematically represented as

         v = \sqrt{\frac{G * M}{r} }

Here G is the gravitational constant with a value

        G = 6.67384 * 10^{-11}

So

      v = \sqrt{\frac{6.67384 * 10^{-11} * 1.90 *10^{41}}{7.40 *10^{20}} }

=>    v = 1.309*10^{5}\ m/s

8 0
3 years ago
Question 5 of 10
snow_tiger [21]

a= v (1) - v (2)/ t = 14 - 10/20 = 4/20 = 0.2 m/s^2 south

8 0
3 years ago
Read 2 more answers
An element is made out of two or more different atoms chemically put together,<br> True<br> Or False
tatyana61 [14]

Answer:

true

Explanation:

it is right

7 0
3 years ago
A violin string has a length of 327mm and produces a note of frequency 440Hz.
Scorpion4ik [409]

The characteristics of the standing wave we can find the backlash for the frequency of the wave when the string is shortened is:

  • The new frequency is f = 657 Hz

<h3>How is a standing wave produced?</h3>

A standing wave is produced when a traveling wave meets an obstacle and bounces, the sum of the two waves results in a wave that does not propagate in space.

In the event that the obstacle is a fixed point, there is a node at this point. The expression for the length of the standing wave.

            L = \frac{\lambda }{2}              fundamental frequency    

            L = 2 \frac{\lambda}{2}            second harmonic          

            L = 3 \frac{\lambda}{2}            third harmonic        

           L = n \frac{\lambda}{2}             general term.

Where L is the length of the chord, lan the wavelength and n an integer.

Wave speed is related to wavelength and frequency.    

       v = λ f.

Let's substitute.          

        v = \frac{2L}{n}  

They indicate that initially the string has a length of L₀ = 327 mm= 0.327m and the frequency is f₀ = 440 Hz.    

          v n = 2L₀ f₀            

          v n = 2 0.327 440            

          v n = 287.76

They indicate that the tension on the string do not changes and the speed of the wave depends only on the tension and the density of the string, therefore it is constant, we assume that the harmonic does not change either, therefore the new length.  

         v n = 2 L f

Let's substitute.          

         287.76 = 2 L f      

         f = \frac{287.76x}{2L}

Let's calculate.      

       f = \frac{287.76}{2 \ 0.219}    

       f = 656.99 Hz

In conclusion with the characteristics of the standing wave we can find the backlash for the frequency of the wave when the string is shortened is:  

  • The new frequency is:  f = 657 Hz

Learn more about standing waves here: brainly.com/question/17031219

6 0
2 years ago
Al enfriar una placa cuadrada metálica de 8 cm de longitud su lado disminuye un 0.03%
Xelga [282]
Acceptame para ser amigos y luego te ayudo
3 0
4 years ago
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