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alexdok [17]
2 years ago
6

A beam of light, initially travelling in the air, strikes water surface at an angle of 24.5° with the normal. If the speed of li

ght in water is 2.22 × 10^8ms^-1, determine the angle of refraction?​
Physics
1 answer:
kykrilka [37]2 years ago
8 0

Answer:

Explanation:

n = 3.00e8/2.22e8 = 1.35

1.00sin24.5 = 1.35sinθ

θ = 17.9°

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What is the magnitude of your displacement when you follow directions that tell you to walk 100.0m north, then 25.0m East?
atroni [7]

Answer:

Displacement from the starting position is 103.21m

Explanation:

If you draw these directions, it will create the two legs of a triangle.

Using this method, you can visualize why your displacement is what it is.

Using the pythagorean theorem

{a}^{2}  +  {b}^{2}  =  {c}^{2}

Plug in both values

{100m}^{2}  +  {25m}^{2}  =  {c}^{2}

c =  \sqrt{10652}

c = 103.2085

c= 103.21

6 0
3 years ago
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Sliva [168]

Answer:hello

Explanation:

6 0
2 years ago
In a physics lab, Asha is given a 10.7 kg uniform rectangular plate with edge lengths 67.3 cm by 53.5 cm . Her lab instructor re
Leya [2.2K]

Answer:

I=2.6363\ kg.m^2

Explanation:

Given:

dimension of uniform plate, (0.673\times 0.535)\ m^2

mass of plate, m=10.7\ kg

Now we find the moment of inertia about the center of mass of the rectangular plate is given as:

I_{cm}=\frac{1}{12} \times m(L^2+B^2)

where:

L= length of the plate

B= breadth of the plate

I_{cm}=\frac{1}{12} \times 10.7\times(0.673^2+0.535^2)

I_{cm}=0.6591\ kg.m^2

We know that the center of mass of the rectangular plane is at its geometric center which is parallel to the desired axis XX' .

Now we find the distance between the center of mass and the corner:

s=\frac{\sqrt{ (0.673^2+0.535^2)}}{2}

s=0.4299\ m

Now using parallel axis theorem:

I=I_{cm}+m.s^2

I=0.6591+10.7\times 0.4299^2

I=2.6363\ kg.m^2

6 0
3 years ago
An airplane has a momentum of 8.55 x 107 kg.m/s[S] and a velocity of 900 km/h[S]. Determine the mass of the airplane.
kow [346]

Answer:

342,000kg

Explanation:

p=mv

8.55*10^7 kg*m/s=m(900 km/h)

85,500,000 kg*m/s=m(900 km/h)

(85,500,000 kg*m/s)/(900 km/h)=m

Get same units.... 900km/h = 250m/s

m/s cancel in the division, you are left with just kg!!

85,500,000/250=342,000kg! That's it!

6 0
3 years ago
a 28.7 KG sled is pulled forward with a 63 net force across the ground with MK equals 0.169 what is the acceleration of the sled
abruzzese [7]

Answer:

0.54\ \text{m/s}^2

Explanation:

F = Force on the sled = 63 N

m = Mass of sled = 28.7 kg

\mu_k = Coefficient of kinetic friction = 0.169

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

The force balance of the system is given by

F-\mu_k mg=ma\\\Rightarrow a=\dfrac{F-\mu_k mg}{m}\\\Rightarrow a=\dfrac{63-0.169\times 28.7\times 9.81}{28.7}\\\Rightarrow a=0.54\ \text{m/s}^2

The acceleration of the sled is 0.54\ \text{m/s}^2.

5 0
3 years ago
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