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Vladimir [108]
3 years ago
15

A 1000-kg car traveling at 70 m/s takes 3 m to stop under full braking. the same car under similar road conditions, traveling at

140 m/s, takes ______________ m to stop under full braking.
Physics
1 answer:
azamat3 years ago
5 0
We assume a=const (acceleration is constant. We apply the equation
v^2=v0^2+2as where s is the distance to stop v=0(m/s). We find the acceleration from this equation
a=-v0^2/(2s)=-70^2/(2*3) =-816.7 (m/s^2)

We know the acceleration, thus we find the distance necesssary to stop when initial speed is v=140 (m/s)
s=-v0^2/(2a) =140^2/(2*816.7)=12 (m)

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8 0
2 years ago
the winner of a 10km road race took half an hour to complete the race. Calculate the average speed. Give your answer in metres p
leonid [27]
Hello there!

For this:

1). Convert 10km to meters!
2). Convert the 30 minutes into seconds!

3). Use the following formula to solve for speed!

speed= distance/time

Note: The units should automatically work out to m/s. :)

My goal is to make sure you understand the problem, which is why I won't be giving you the answer. It'll be more work now, but less work in the future! :)

Hope this helped!

-------------


DISCLAIMER: I am not a professional tutor or have any professional background in your subject. Please do not copy my work down, as that will only make things harder for you in the long run. Take the time to really understand this, and it'll make future problems easier. I am human, and may make mistakes, despite my best efforts. Again, I possess no professional background in your subject, so anything you do with my help will be your responsibility. Thank you for reading this, and have a wonderful day/night!
4 0
3 years ago
If the object represented by the FBD below has a mass of 2.5 kg, what is the acceleration of the object?
Debora [2.8K]

Answer:

4 m/s² down

Explanation:

We'll begin by calculating the net force acting on the object.

The net force acting on the object from the left and right side is zero because the same force is applied on both sides.

Next, we shall determine the net force acting on the object from the up and down side. This can be obtained as follow:

Force up (Fᵤ) = 15 N

Force down (Fₔ) = 25 N

Net force (Fₙ) =?

Fₙ = Fₔ – Fᵤ

Fₙ = 25 – 15

Fₙ = 10 N down

Finally, we shall determine the acceleration of the object. This can be obtained as follow:

Mass (ml= 2.5 Kg

Net force (Fₙ) = 10 N down

Acceleration (a) =?

Fₙ = ma

10 = 2.5 × a

Divide both side by 2.5

a = 10 / 2.5

a = 4 m/s² down

Therefore, the acceleration of the object is 4 m/s² down

6 0
3 years ago
A downhill skier was able to move 560 meters in 25 seconds. What is the skier’s average speed? (Round your answer to the nearest
anastassius [24]
The average speed of a moving body is given by:
average speed = total distance / total time
average speed = 560 / 25
22.4 meters per second

The skier is traveling at an average velocity of 22.4 meters per second.
7 0
3 years ago
Read 2 more answers
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