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Mice21 [21]
3 years ago
9

A reversible Carnot engine has an efficiency of 30% and it operates between a heat source maintained at T 1 , and a refrigerator

maintained at 210 K. Find the temperature of the heat source.
Physics
1 answer:
bixtya [17]3 years ago
6 0

To solve this problem we will apply the concepts related to the thermal efficiency given in an engine of the Carnot cycle. Here we know that efficiency is given under the equation

\eta = 1 - \frac{T_2}{T_1}

Where,

T_2 = Temperature of Cold Body

T_1 =Temperature of Hot Body

\eta= Efficiency

According to the statement our values are:

\eta = 0.3

T_2 = 210K

Replacing we have that

0.3 = 1- \frac{210}{T_1}

\frac{210}{T_1} = 0.7

T_1 = \frac{210}{0.7}

T_1 = 300K

Therefore the temperature of the heat source is 300K

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A car of 900 kg mass is moving at the velocity of 60 km/hr. It is brought into rest at 50 meter distance by applying a brake. No
kozerog [31]

Answer: -2502N

Explanation:

(V_2)^2=(V_1)^2+2ad

where;

V_2 = final velocity = 0

V_1 = initial velocity = 60 km/h = 16.67 m/s

a = acceleration

d = distance

First all of, because acceleration is given in m/s and not km/h, you need to convert 60km/h to m/s. Our conversion factors here are 1km = 1000m and 1h = 3600s

60km/h(\frac{1000m}{1km} )(\frac{1h}{3600s} )=16.67m/s

Solve for a;

(V_2)^2=(V_1)^2+2ad

Begin by subtracting (V_1)^2

(V_2)^2-(V_1)^2=2ad

Divide by 2d

\frac{(V_2)^2-(V_1)^2}{2d} =a

Now plug in your values:

a=\frac{(0)^2-(16.67 m/s)^2}{2(50m)}

a=\frac{0-277.89m^2/s^2}{100m}

a=-2.78m/s

If you're wondering why I calculated acceleration first is because in order to find force, we need 2 things: mass and acceleration.

F=ma

m = mass = 900kg

a = acceleration = -2.78m/s

F=(900kg)(-2.78m/s)\\F=-2502N

It's negative because the force has to be applied in the opposite direction that the car is moving.

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I haven´t learned that yet I´m sorry.
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Answer;

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Explanation;

Position-Time graphs display the motion of a object by showing the changes of velocity with respect to time.

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