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STatiana [176]
3 years ago
5

What do radio waves and microwaves have in common?

Physics
2 answers:
Tamiku [17]3 years ago
5 0

Answer:

I Will say the Answer is A

Explanation:

PSYCHO15rus [73]3 years ago
5 0
Both have lower radiant energy than visible light. Both have higher frequencies than visible light. Both are located to the right of visible light on the spectrum


Hopefully this helps if not i’m sorry
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On the moon what would be the force of gravity acting on an object that has a mass of 7 kg?
Rudiy27

Answer:

0

Explanation:

4 0
4 years ago
Sprinting near the end of a race, a runner with a mass 63 kg accelerates from a speed of 25 m/s to a speed of 26 m/s in 54 s. To
gavmur [86]

Answer:

1.1655 N

Explanation:

Given that,

Initial speed, u = 25 m/s

Final speed, v = 26 m/s

Time taken, t = 54 s

So, Applying equation of motion as:

v=u+at\\\Rightarrow a=\frac{v-u}{t}\\\Rightarrow a=\frac{26-25}{54}\ m/s^2\\\Rightarrow a=0.0185\ m/s^2

According to the Newton's second law of motion:-

Force=Mass\times Acceleration

Mass = 63 kg

So,

Force=63\times 0.0185\ kgm/s^2

<u>Force = 1.1655 N</u>

5 0
4 years ago
A 44 kg block lies on a horizontal frictionless surface. A horizontal force of 110 N is applied to the block. (a) Determine the
Oksana_A [137]
44k jkjk know the answer
8 0
3 years ago
Which statement best describes the atoms in a gas?
MariettaO [177]

Answer:

They move freely in all directions

Explanation:

7 0
3 years ago
Ocean waves travel in to the beach at an average velocity of 2.5 m/s
ANTONII [103]

1) D) 10.0 m

To find the average distance between the wave peaks, we can use the formula:

v=\frac{d}{t}

where in this case:

v = 2.5 m/s is the average velocity

d = ? is the average distance

t = 4 s is the time between two wave peaks

Re-arranging the equation, we find

d=vt=(2.5 m/s)(4 s)=10.0 m

2) B) Power

This is exactly the definition of power. In fact, power is defined as the ratio between the amount of work done / of energy used, and the time taken for this conversion to occur:

P=\frac{W}{t}

where

W is the amount of work done / of energy used

t is the time taken

3) C) The body builder uses the same energy and but more power.

The energy used by the body builder does not change: in fact, it is only related to the height at which he lift the weight. The work done to lift the weight, of mass m, up to a height of h, is given by

W=mgh

where g is the gravitational acceleration. So, this quantity does not change. Instead, the power changes, because the time the body builder takes to lift the weight up has decreased, and the power depends on the time as we know from the formula:

P=\frac{W}{t}

so, since t has decreased, P has increased.

4) D) body mass, final height, and the time required to complete the climb

The power output is given by:

P=\frac{W}{t}=\frac{mgh}{t}

where:

m is the body mass

g is the gravitational acceleration

h is the final height

t is the time required to complete the climb

Therefore, we see that correct choice is D.

5 0
3 years ago
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