Gauss’s Law for magnetism
Answer: If the woodpecker drums upon a tree 5 times in one second, then the frequency is 5 Hz; each drum must endure for one-fifth a second, so the period is 0.2 s.
Answer:
Explained
Explanation:
Big Bang happened about 13.7 billion years ago. It is most accepted theory of universe creation. Several experiments have confirmed the happening of big bang back then, in promising way. One of this experiment is the red shift experiment. A scientist named Edwin Hubble tried to study the spectrum of stars. He made a shocking revelation that universe is rushing outwards in all directions. Light travelling away registers on the red side. He observed that the distance stars showed red shift in accelerated manner. If the universe is accelerating that means, at one point it would have been smaller, in fact it was as small as an atom, some how it exploded and lead to formation of the expanding universe.
the state or quality of being efficient.
"greater energy efficiency"
Answer
Efficiency is the ability to avoid wasting materials, energy, efforts, money, and time in doing something or in producing a desired result.
Answer:
Part a)

Part b)

Explanation:
As we know that by parallel axis theorem we will have

Part a)
here we know that for a stick the moment of inertia for an axis passing through its COM is given as

now if we need to find the inertia from its end then we will have



Part b)
here we know that for a cube the moment of inertia for an axis passing through its COM is given as

now if we need to find the inertia about an axis passing through its edge


