Answer:
2.26 s
Explanation:
The following data were obtained from the question:
Height (h) = 25 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =..?
The time taken for the egg to hit the floor can be obtained as illustrated below:
h = ½gt²
25 = ½ × 9.8 × t²
25 = 4.9 × t²
Divide both side by 4.9
t² = 25 / 4.9
Take the square root of both side
t = √(25 / 4.9)
t = 2.26 s
Thus, it will take 2.26 s for the egg to hit the floor.
Answer:
482.4 kg
Explanation:
104 calorie = 435344 J
The 2.5% of this energy equals to
435344 * 0.0025 = 10883.6 J
If this energy is converted to work done on lifting a barbell by a distance of 2.3. By the formula of Work W = force * distance then the force he exerts on the barbell is

Assuming gravitational constant g = 9.81 m/s2 then the mass of the barbell is
m = 4732 / 9.81 = 482.4 kg
At eccentricity = 0 we get a circle For 0 < eccentricity < 1 we get an ellipse for eccentricity = 1 we get a parabola for eccentricity > 1 we get a hyperbola for infinite eccentricity we get a lineSHOW FULL ANSWER