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Wewaii [24]
3 years ago
13

Does someone have hamster name recommendation (girl hamster)

Physics
1 answer:
ExtremeBDS [4]3 years ago
5 0

Explanation:

Lola

Or Jasmine

Or lucy

Or Nightingale

Or Sugarcane

Or Polly

Or Heather

Some names I like!

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A force of 350N is applied to a body. If the work done is 40kJ, what is the distance through which the body moved?
Studentka2010 [4]

The distance covered by the body is 114.3 m

Explanation:

The work done by a force exerted on an object is given by

W=Fd cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

For the object in this problem, we have

F = 350 N is the force applied

W=40 kJ = 40,000 J is the work done

\theta=0^{\circ} if we assume that the force is applied parallel to the motion of the object

Solving for d, we find the distance covered by the object:

d=\frac{W}{F cos \theta}=\frac{40,000}{(350)(cos 0)}=114.3 m

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

7 0
3 years ago
4. An object is thrown from from the ground upward with an initial speed of 3.75 m/s. How long will the object be in the air bef
Natali [406]

Answer:

Explanation:

There's an easy way to answer this and then an easier way. I'll do both since I'm not sure what you're doing this for: physics or calculus. Calculus is the easier way, btw.

Going with the physics version first, here's what we know:

a = -9.8 m/s/s

v₀ = 3.75 m/s

t = ??

That's not a whole lot...at least not enough to directly solve the problem. What we have to remember here is that at the max height of a parabolic path, the final velocity is 0. So we can add that to our info:

v = 0 m/s. Use the one-dimensional equation that utilizes all that info and allows us to solve for time:

v = v₀ +at and filling in:

0 = 3.75 + (-9.8)t and

-3.75 = -9.8t so

t = .38 seconds. This is how long it takes to get to its max height. Another thing we need to remember (which is why calculus is so much easier!) is that at the halfway point of a parabolic path (the max height), the object has traveled half the time it takes to make the whole trip. In other words, if .38 is how long it takes to go halfway, then 2(.38) is how long the whole trip takes:

2(.38) = .76 seconds. Now onto the calculus way:

The position function is

s(t)=-4.9t^2+3.75t The first derivative of this is the velocity function and, knowing that when the velocity is 0, the time is halfway gone, we will find the velocity function and then set it equal to 0 and solve for t:

v(t) = -9.8t + 3.75 and

0 = -9.8t + 3.75 and

-3.75 = -9.8t so

t = ,38 and multiply that by 2 to find the time the whole trip took:

2(.38) = .76 seconds.

6 0
3 years ago
two protons are released from rest when they are 0.750 nm apart (a)what is the maximum speed they will reach ? when does this sp
Keith_Richards [23]

Answer:

And so calculating we get the maximum speed at each proton will reach To be 1.36 Times 10 to the four m the second

8 0
2 years ago
A projectile is fired straight upward at 173 m/s. how fast is it moving at the instant it reaches the top of its trajectory?
Fittoniya [83]
The top of the trajectory is the point where it changes from rising to falling. At that exact instant, its vertical speed is zero.
8 0
3 years ago
The specific heat of a solid Y is 11.5 cal/g°C. A sample of this
fgiga [73]

The sample of the solid in grams is 5.5g

HOW TO CALCULATE SPECIFIC HEAT CAPACITY:

  • The quantity of heat absorbed or released by a substance can be calculated using the following formula:

Q = m × c × ∆T

Where;

Q = quantity of heat absorbed/released (cal)

m = mass of the substance (g)

c = specific heat (cal/g°C)

∆T = change in temperature (°C)

  • According to the information provided in this question:

Q = 7.90Kcal = 7900cal

m = ?

c = 11.5 cal/g°C

T1 = 135K = 135K − 273.15 = -138.1°C

T2 = 260K = 260K − 273.15 = -13.15°C

∆T = -13.15 - (-138.1) = 124.95°C

  • Hence, the mass of the substance can be calculated as follows:

m = Q ÷ c∆T

m = 7900 ÷ (11.5 × 124.95)

m = 7900 ÷ 1436.93

m = 5.5grams.

Therefore, the sample of the solid in grams is 5.5g.

Learn more: brainly.com/question/21643161?referrer=searchResults

5 0
2 years ago
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