The distance covered by the body is 114.3 m
Explanation:
The work done by a force exerted on an object is given by

where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
For the object in this problem, we have
F = 350 N is the force applied
is the work done
if we assume that the force is applied parallel to the motion of the object
Solving for d, we find the distance covered by the object:

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Answer:
Explanation:
There's an easy way to answer this and then an easier way. I'll do both since I'm not sure what you're doing this for: physics or calculus. Calculus is the easier way, btw.
Going with the physics version first, here's what we know:
a = -9.8 m/s/s
v₀ = 3.75 m/s
t = ??
That's not a whole lot...at least not enough to directly solve the problem. What we have to remember here is that at the max height of a parabolic path, the final velocity is 0. So we can add that to our info:
v = 0 m/s. Use the one-dimensional equation that utilizes all that info and allows us to solve for time:
v = v₀ +at and filling in:
0 = 3.75 + (-9.8)t and
-3.75 = -9.8t so
t = .38 seconds. This is how long it takes to get to its max height. Another thing we need to remember (which is why calculus is so much easier!) is that at the halfway point of a parabolic path (the max height), the object has traveled half the time it takes to make the whole trip. In other words, if .38 is how long it takes to go halfway, then 2(.38) is how long the whole trip takes:
2(.38) = .76 seconds. Now onto the calculus way:
The position function is
The first derivative of this is the velocity function and, knowing that when the velocity is 0, the time is halfway gone, we will find the velocity function and then set it equal to 0 and solve for t:
v(t) = -9.8t + 3.75 and
0 = -9.8t + 3.75 and
-3.75 = -9.8t so
t = ,38 and multiply that by 2 to find the time the whole trip took:
2(.38) = .76 seconds.
Answer:
And so calculating we get the maximum speed at each proton will reach To be 1.36 Times 10 to the four m the second
The top of the trajectory is the point where it changes from rising to falling. At that exact instant, its vertical speed is zero.
The sample of the solid in grams is 5.5g
HOW TO CALCULATE SPECIFIC HEAT CAPACITY:
- The quantity of heat absorbed or released by a substance can be calculated using the following formula:
Q = m × c × ∆T
Where;
Q = quantity of heat absorbed/released (cal)
m = mass of the substance (g)
c = specific heat (cal/g°C)
∆T = change in temperature (°C)
- According to the information provided in this question:
Q = 7.90Kcal = 7900cal
m = ?
c = 11.5 cal/g°C
T1 = 135K = 135K − 273.15 = -138.1°C
T2 = 260K = 260K − 273.15 = -13.15°C
∆T = -13.15 - (-138.1) = 124.95°C
- Hence, the mass of the substance can be calculated as follows:
m = Q ÷ c∆T
m = 7900 ÷ (11.5 × 124.95)
m = 7900 ÷ 1436.93
m = 5.5grams.
Therefore, the sample of the solid in grams is 5.5g.
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