AgNO₃ will act as the oxidising agent.
<h3><u>For the given chemical equation:</u></h3>
Cu + 2AgNO₃ → 2Ag + Cu(NO₃)₂
Half reactions for the given chemical reaction:
<u>Reducing agent:</u>
Cu → Cu²⁺ + 2e⁻
Copper is a reducing agent because it is losing 2 electrons, which causes an oxidation process.
<u>Oxidising Agent</u>:
Ag⁺ + e⁻ → Ag
The silver ion undergoes a reduction process and is regarded as an oxidizing agent since it is acquiring one electron per atom.
Hence, AgNO₃ is considered as an oxidizing agent and therefore the correct answer is Option B.
<h3><u>
Oxidising and Reducing agents</u></h3>
- An oxidizing agent is a substance that reduces itself after oxidizing another material. It passes through a reduction process in which it obtains electrons and the substance's oxidation state is decreased.
- A reducing agent is a chemical that oxidizes after reducing another material. It passes through an oxidation process in which it loses electrons and the substance's oxidation state increases.
To know more about the process of Oxidation and Reduction, refer to:
brainly.com/question/4222605
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Because they are farther across the periodic table<span />
Answer:
0.144M
Explanation:
First, let us write a balanced equation for the reaction. This is illustrated below:
HNO3 + KOH —> KNO3 + H20
From the equation,
nA = 1
nB = 1
From the question given, we obtained the following:
Ma =?
Va = 30.00mL
Mb = 0.1000M
Vb = 43.13 mL
MaVa / MbVb = nA/nB
Ma x 30 / 0.1 x 43.13 = 1
Cross multiply to express in linear form
Ma x 30 = 0.1 x 43.13
Divide both side by 30
Ma = (0.1 x 43.13) /30 = 0.144M
The molarity of the nitric acid is 0.144M
There would be 67 left because you do
Answer:
Mg²⁺
Explanation:
The electron configuration of Mg is [Ne]3s².
It is easier for Mg to get a complete octet by losing two electrons and exposing the neon core than it is to add eight electrons and get an Ar octet.
The most stable monatomic Mg ion is Mg²⁺.
