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marta [7]
3 years ago
8

Nicole is planting a rectangular garden in her backyard. She wants the length of the garden to be 5 yards. The area of the garde

n must be at most 30 square yards. (Nicole doesn't want to buy any more soil.) Write an inequality that describes the possible widths (in yards) of the garden.
Mathematics
1 answer:
Morgarella [4.7K]3 years ago
8 0

The inequality that best describes the width of the garden is

Width ≤ 6 yards

Area ≤ Length* Width

<h3>Given data</h3>

Length = 5 yards

Width = ??

Area = 30 square yards

From the formula of the area of rectangle we have

Area = Length * Width

Let the width be x

Substitute

30 = 5 * x

30 = 5x

Divide both sides by 5

x = 30/5

x = 6 yards

Hence the with should be less than or equal to 6 yards

Learn more about area of rectangle here:

brainly.com/question/2607596

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−5x+2y=9<br> y=7x<br> ​x=<br> y=
Serhud [2]

- 5x+2y=9 \\ y=7x

We know that y=7x, so we just need tu put it into the 1st equation

- 5x + 2 \times 7x = 9 \\  - 5x + 14x = 9 \\ 9x = 9 | \div 9 \\ 9x \div 9 = 9 \div 9 \\ x = 1

So we found x. Now we can find y

y = 7 \times 1 \\ y = 7

Answer:

x=1, y=7; or (1;7)

4 0
3 years ago
Read each verbal expression Then assign a variable and distribute
Sedaia [141]
5. 2*(7+x) which if you distributed would be 14+2x.
6.x - 8^2 or x-64.
Hope this helped!
4 0
4 years ago
We want to find the zeros of this polynomial:
USPshnik [31]
Answer: x-intercept = -1, 1, 2, 3
4 0
3 years ago
Marie asked 25 fellow sixth graders
aleksandr82 [10.1K]

Answer:

She can expect 240 to say no.

6 0
3 years ago
Read 2 more answers
Using the quadratic formula to solve x2 = 5 - X, what are the values of X?
sdas [7]

Answer:

The answer is

<h3>x =  \frac{ - 1 +  \sqrt{21} }{2}  \:  \:  \: or \:  \:  \: x =  \frac{ - 1 -  \sqrt{21} }{2}</h3>

Step-by-step explanation:

x² + x - 5 = 0

Using the quadratic formula

That's

<h3>x =  \frac{  - b\pm \sqrt{ {b}^{2} - 4ac } }{2a}</h3>

From the question

a = 1 , b = 1 , c = - 5

Substitute the values into the above formula and solve

We have

<h3>x =  \frac{ - 1\pm \sqrt{ {1}^{2} - 4(1)( - 5) } }{2(1)}  \\ x =  \frac{ - 1\pm \sqrt{1  + 20 } }{2}  \\ x =   \frac{ - 1\pm \sqrt{21} }{2}</h3>

We have the final answer as

<h3>x =  \frac{ - 1 +  \sqrt{21} }{2}  \:  \:  \: or \:  \:  \: x =  \frac{ - 1 -  \sqrt{21} }{2}</h3>

Hope this helps you

3 0
3 years ago
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