Answer:
Explanation:
β decay is a process in which a nucleus emits an electron.
The nuclear symbol for a β particle is
l
0
-1
e
.
In any nuclear equation, the sum of the subscripts (atomic numbers,
Z
) and the sum of the superscripts (atomic masses,
M
) must be equal on each side of the equation.
For the β decay of iodine 131, we have
131
53
I
→
l
M
Z
X
+
l
0
-1
e
Hence
131
=
M
+
0
, so
M
=
131
53
=
Z - 1
, so
Z
=
53
+
1
=
54
The element
X
with
Z = 54
is
Xe
.
So the equation is
131
53
I
→
131
54
Xe
+
l
0
-1
e
Note that in β decay, the product has the same mass number but an atomic number that has increased by 1.
Answer:
2-methylpropan-2-ol
Explanation:
In this case, we can start with a linear structure of 3 carbons. In carbon 2 we can put a methyl group (). In this same carbon we can put the "OH" group and we will obtain "<u>2-methylpropan-2-ol</u>".
In this molecule, the central atom has 3 bonds with another carbons, so, this central atom is a teritary one. Therefore, we will have a <u>tertiary alcohol.</u>
See figure 1
D is the correct answer hope this helps
B). Visible Light. Hope that helps
Answer:
2) lose electrons and form positive ions
Explanation:
Metals are generally electropositive elements due to the fact that they lose electrons to their non-metal counterparts and hence, form CATIONS or positively charged atoms. Non-metals, on the contrary, gains electrons and become negatively charged i.e form anions. These ions combine to form stable ionic compounds.
This electron-losing characteristics of metals make them have properties that includes: good conductors of electricity and heat, being lustrous etc.