Small particles that settle out of wind and water are called.
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The energy transferred on the object is 1000 Joules.
Given:
An object on which a constant force of 100 N was applied to displace it over a distance of 10 meters.
To find:
The energy transfer occurs on the object.
Solution
The force applied on the object = F = 100 N
The displacement of the object = d = 10 m
The energy transferred on the object or work done is given by:
The energy transferred on the object is 1000 Joules.
Learn more about work done here:
<h3>Answer:</h3>
112.08 mL
<h3>Explanation:</h3>From the question we are given;
- Initial volume, V1 = 100.0 mL
- Initial temperature, T1 = 225°C, but K = °C + 273.15
thus, T1 = 498.15 K
- Initial pressure, P1 = 1.80 atm
- Final temperature , T2 = -25°C
= 248.15 K
- Final pressure, P2 = 0.80 atm
We are required to calculate the new volume of the gases;
- According to the combined gas law equation;
Rearranging the formula;
Therefore;
Therefore, the new volume of the gas is 112.08 mL
That acid rain has lowered the ph of a particular lake to ph 5.0. the hydroxide ion concentration of this lake is
1 × 10^-9 mol of hydroxide ions per liter of lake water
pH + pOH = 14
pOH = 14 - 5
pOH = 9.00
pOH = -log [OH⁻]
[OH⁻] = 10^-pOH
[OH⁻] = mol
Therefore,
the hydroxide ion concentration of this lake is 1 × 10^-9 mol
To learn more about Concentration
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