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Contact [7]
3 years ago
14

1500 kg car traveling at 15 m/s collides with a 500 kg moose which is at

Physics
1 answer:
zhannawk [14.2K]3 years ago
3 0

Answer:

the car will slow down due to the change in speed

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If you drop a baseball and let it fall, gravity from Earth pulls down on the baseball with 1.4 N of force. What is the reaction
myrzilka [38]

The reaction force in this situation occur once it hits the ground, and normal force from Earth's surface will push up on the ball with 1.4 N.

<em>The correct answer is option (</em><em>C</em><em>) </em>

<h3>What is Newton's third law of motion?</h3>

Newton's third law of motion states that for every action there is equal and opposite reaction.

Mathematically, this law is given as;

Fa = Fb

where;

  • Fa is the force applied by object A
  • Fb is the reaction experienced by object B

The force applied by object is equal and opposite the reaction experienced by object B.

When an object placed on the floor, the weight of the object acts downward while the normal reaction of the object acts upwards.

Thus, if you drop a baseball and let it fall, gravity from Earth pulls down on the baseball with 1.4 N of force, the reaction force will occur once it hits the ground, as the normal force from Earth's surface will push up on the ball with 1.4 N.

Learn more about reaction force here: brainly.com/question/1013858

#SPJ1

5 0
1 year ago
A 0.005 kg bullet is travelling horizontally at a velocity of 250 m/s when it strikes a wooden block of mass 12 kg on a table at
Verdich [7]
Use the conservation of momentum formula: m1v1 + m2v2 = v(m1 + m2)

(0.005kg)(250m/s) + (12kg)(0m/s) = v(0.005kg + 12kg)

v = ((0.005kg)(250m/s)) / (0.005kg + 12kg)

v = 0.104 m/s
6 0
4 years ago
Plants absorb WHAT from the atmosphere and release WHAT to the atmosphere.
makvit [3.9K]
Plants absorb water and release o2
6 0
3 years ago
Read 2 more answers
How much energy is required to vaporize 100g of water at its boiling point?
Karolina [17]
Latent heat fusion(l)=540

∆t= temp(100-0)

Q=ml+ms∆T

Q=500.100+100.1.100
Q=64000 cal


5 0
3 years ago
How much GPE is stored when an 80kg astronaut climbs to the top of a 5m high lunar lander? The gravity strength on the moon is 1
8_murik_8 [283]

Answer:

The GPE, stored is 640 Joules

Explanation:

The given parameters are;

The given mass of the astronaut, m = 80 kg

The height of the top of the lunar lander to which the astronaut climbs, h = 5 m

The gravity strength on the moon, g = 1.6 N/kg

The Gravitational Potential Energy, GPE, stored is given according to the following equation;

GPE stored = m·g·h

Therefore, by substituting the known values, we have;

GPE Stored = 80 kg × 1.6 N/kg × 5 m = 640 Joules

The GPE, stored = 640 Joules.

6 0
3 years ago
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