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AleksAgata [21]
2 years ago
11

Which pair of elements form an ionic bond with

Chemistry
2 answers:
Vesna [10]2 years ago
5 0

Answer:

It's only A

Explanation:

Potassium (K) is a metal and Chlorine (Cl) is a nonmetal, and ionic compounds are formed between metals and nonmetals. So KCl forms ionic bonds.

Hydrogen (H) and Chlorine (Cl) are both nonmetals, and only covalent bonds form between nonmetals. (Only exception is when its an acid, then it's ionic)

Also, the question indicated which "pair" and not "pairs" meaning that there is only one answer, and I'm more likely to go with A rather than D.

KATRIN_1 [288]2 years ago
3 0

Answer:

Yes Both A) KCL and D) HCL are correct...

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Ionic bonds form between which two types of elements?​
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Answer:

Ionic bonds usually occur between metal and nonmetal ions. For example, sodium (Na), a metal, and chloride (Cl), a nonmetal, form an ionic bond to make NaCl.

Explanation:

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In the following equation, which element has been reduced?
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Determine the maximum number of electrons in the 2f designation
sergejj [24]
Google said

How many electrons fit in each shell around an atom?

The maximum number of electrons that can occupy a specific energy level can be found using the following formula:

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(Principal Quantum Number) Shell Letter Electron Capacity
1 K 2
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4 0
3 years ago
Calculate the standard enthalpy change for the reaction at 25 ∘C. Standard enthalpy of formation values can be found in this lis
weqwewe [10]

Answer:

\Delta H_{rxn}=-2043.999kJ

Explanation:

\Delta H_{rxn}^{0}=\sum [n_{i}\times \Delta H_{f}^{0}(product)_{i}]-\sum [n_{j}\times \Delta H_{f}^{0}(reactant_{j})]

Where n_{i} and n_{j} are number of moles of product and reactant respectively (equal to their stoichiometric coefficient).

\Delta H_{f}^{0} is standard heat of formation and \Delta H_{rxn}^{0} is standard enthalpy change for reaction at 25^{0}\textrm{C}

So, \Delta H_{rxn}=[3mol\times \Delta H_{f}^{0}(CO_{2})_{g}]+[4mol\times \Delta H_{f}^{0}(H_{2}O)_{g}]-[1mol\times \Delta H_{f}^{0}(C_{3}H_{8})_{g}]-[5mol\times \Delta H_{f}^{0}(O_{2})_{g}]

or, \Delta H_{rxn}=[3mol\times -393.509kJ/mol]+[4mol\times -241.818kJ/mol]-[1mol\times -103.8kJ/mol]-[5mol\times 0kJ/mol]

or, \Delta H_{rxn}=-2043.999kJ

4 0
3 years ago
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