Answer:
#2) The spaceship's forward motion must be slowed down so the earth's gravitational pull on it will be stronger than the ship's forward motion.
Answer:
424.26 m/s
Explanation:
Given that Two air craft P and Q are flying at the same speed 300m/s. The direction along which P is flying is at right angles to the direction along which Q is flying. Find the magnitude of velocity of the air craft P relative to air craft Q
The relative speed will be calculated by using pythagorean theorem
Relative speed = sqrt(300^2 + 300^2)
Relative speed = sqrt( 180000 )
Relative speed = 424.26 m/s
Therefore, the magnitude of velocity of the air craft P relative to air craft Q is 424.26 m/s
The specific heat of the metal, assuming no heat is exchanged with the surroundings is 2140 J/(kg•K).
<h3>
Specific heat capacity of the metal</h3>
The specific heat capacity of the metal is determined from the principle of conservation of energy.
energy lost by the metal = energy gained by aluminum + energy gained by water
Q = mcΔθ
where;
- m is mass (kg)
- c is specific heat capacity
- Δθ is change in temperature
0.425c(100 - 40) = 0.1(900)(40 - 15) + 0.5(4186)(40 - 15)
25.5c = 2250 + 52,325
c = 54,575/25.5
c = 2140 J/(kg•K)
Learn more about specific heat capacity here: brainly.com/question/21406849
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Answer:
H(max) = (v²/2g)
Explanation:
The maximum height the ball will climb will be when there is no friction at all on the surface of the hill.
Normally, the conservation of kinetic energy (specifically, the work-energy theorem) states that, the change in kinetic energy of a body between two points is equal to the work done in moving the body between the two points.
With no frictional force to do work, all of the initial kinetic emergy is used to climb to the maximum height.
ΔK.E = W
ΔK.E = (final kinetic energy) - (initial kinetic energy)
Final kinetic energy = 0 J, (since the body comes to rest at the height reached)
Initial kinetic energy = (1/2)(m)(v²)
Workdone in moving the body up to the height is done by gravity
W = - mgH
ΔK.E = W
0 - (1/2)(m)(v²) = - mgH
mgH = mv²/2
gH = v²/2
H = v²/2g.
