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ra1l [238]
3 years ago
11

Solve 1 for x if a=-9.8, v=2.7, and t= 35​

Physics
2 answers:
aliina [53]3 years ago
6 0

Explanation:

x=VT+at²/2

x=2.7x35+9.8x(35)²/2

x=6097

bonufazy [111]3 years ago
5 0

Answer:

6097 = x

Explanation:

x = VT + at²/2

x= 2.7 * 35 + 9.8 * (35)²/2

x=6097

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A rubber ball is dropped and bounces vertically from a horizontal concrete floor. If the ball has a speed of 3 m/s just before s
Ganezh [65]

Answer:

F=12.5N

Explanation:

Net force = rate of change of momentum

F = m*a

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6 0
3 years ago
If you were to triple the size of the Earth (R = 3R⊕) and double the mass of the Earth (M = 2M⊕), how much would it change the g
EastWind [94]

Answer:

Decreased by a factor of 4.5

Explanation:

"We have Newton formula for attraction force between 2 objects with mass and a distance between them:

F_G = G\frac{M_1M_2}{R^2}

where G =6.67408 × 10^{-11} m^3/kgs^2 is the gravitational constant on Earth. M_1, M_2 are the masses of the object and Earth itself. and R distance between, or the Earth radius.

So when R is tripled and mass is doubled, we have the following ratio of the new gravity over the old ones:

\frac{F_G}{f_g} = \frac{G\frac{M_1M_2}{R^2}}{G\frac{M_1m_2}{r^2}}

\frac{F_G}{f_g} = \frac{\frac{M_2}{R^2}}{\frac{m_2}{r^2}}

\frac{F_G}{f_g} = \frac{M_2}{R^2}\frac{r^2}{m_2}

\frac{F_G}{f_g} = \frac{M_2}{m_2}(\frac{r}{R})^2

Since M_2 = 2m_2 and r = R/3

\frac{F_G}{f_g} = \frac{2}{3^2} = 2/9 = 1/4.5

So gravity would have been decreased by a factor of 4.5  

8 0
3 years ago
What is the force on a 1000 kg elevator that is free falling at 9.8 m/s/s?
Anton [14]

Answer:

Explanation:

Force = (mass) · (acceleration)

= (1,000 kg) · (9.8 m/s²)

= 9,800 newtons

4 0
3 years ago
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