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3 years ago

Solve 1 for x if a=-9.8, v=2.7, and t= 35

Physics

2 answers:

aliina [53]3 years ago

6 0

Explanation:

x=VT+at²/2

x=2.7x35+9.8x(35)²/2

x=6097

bonufazy [111]3 years ago

5 0

Answer:

6097 = x

Explanation:

x = VT + at²/2

x= 2.7 * 35 + 9.8 * (35)²/2

x=6097

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Why does it take significantly stronger magnetic and electric field strengths to move the beam of alpha particles compared with

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3 years ago

Aloop of wire of area 71 cm^2 is placed with its plane parallel to a 16 mt magnetic field. the loop is then rotated so that its

kkurt [141]

Answer:

Approximately 1.62 × 10⁻⁴ V.

Explanation:

The average EMF in the coil is equal to

$\displaystyle \frac{\text{Final Magnetic Flux} - \text{Initial Magnetic Flux}}{2}$ ,

Why does this formula work?

By Faraday's Law of Induction, the EMF $\epsilon$ induced in a coil (one loop) is equal to the rate of change in the magnetic flux $\Phi$ through the coil.

$\displaystyle \epsilon(t) = \frac{d}{dt}(\Phi(t))$ .

Finding the average EMF in the coil is similar to finding the average velocity.

$\displaystyle \text{Average}\; \epsilon = \frac{1}{t}\int_0^t \epsilon(t)\cdot dt$ .

However, by the Fundamental Theorem of Calculus, integration reverts the action of differentiation. That is:

$\displaystyle \int_0^{t} \epsilon(t)\cdot dt = \int_0^{t} \frac{d}{dt}\Phi(t)\cdot dt = \Phi(t) - \Phi(0)$ .

Hence the equation

$\displaystyle \text{Average}\; \epsilon = \frac{1}{t}\int_0^t \epsilon(t)\cdot dt = \frac{\Phi(t)- \Phi(0)}{t}$ .

Note that information about the constant term in the original function will be lost. However, since this integral is a definite one, the constant term in $\Phi(t)$ won't matter.

Apply this formula to this question. Note that $\Phi$ , the magnetic flux through the coil, can be calculated with the equation

$\Phi = B \cdot A \cdot N \; \sin{\theta}$ .

For this question,

$B = \rm 16\; mT = 16\times 10^{-3}\; T$ is the strength of the magnetic field.
$A = \rm 71\; cm^{2} = 71\times \left(10^{-2}\right)^2 \; m^{2}$ is the area of the coil.
$N = 1$ is the number of loops in the coil.
$\theta$ is the angle between the field lines and the coil.
At $\rm 0\;s$ , the field lines are parallel to the coil, $\theta = 0^{\circ}$ .
At $\rm 0.7\; s$ , the field lines are perpendicular to the coil, $\displaystyle \theta = 90^{\circ}$ .

Initial flux: $\Phi(0)= 0$ .

Final flux: $\Phi(0.7) = \rm 1.1136\times 10^{-4}\; Wb$ .

Average EMF, which is the same as the average rate of change in flux:

$\displaystyle \frac{\Phi(0.7) - \Phi(0)}{0.7} \approx\rm 1.62\times 10^{-4}\; V$ .

8 0

3 years ago

Oxygen is one of the reactants, and a large amount of energy is released

zvonat [6]

Answer:

because it undergo combustion

Explanation:

and when combustion takes place high amount of energy is released

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3 years ago

A 310-N child is in a swing that is attached to a pair of ropes 2.10 m long. Find the gravitational potential energy of the chil

Softa [21]

Explanation:

Given that,

Force acting on the child, F = 310 N

Length of the ropes, d = 2.1 m

We need to find the gravitational potential energy of the child–Earth system relative to the child's lowest position when the ropes are horizontal. The potential energy is simply given by :

$E=(mg)\times d\\\\E=F\times d\\\\E=310\ N\times 2.1\ m\\\\E=651\ J$

Hence, this is the required solution.

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3 years ago

Solve 1 for x if a=-9.8, v=2.7, and t= 35​

Solve 1 for x if a=-9.8, v=2.7, and t= 35