The question extends beyond what I already know.
The question makes me curious.
Answer:
A body travels 10 meters during the first 5 seconds of its travel,and a total of 30 meters over the first 10 seconds of its travel
20miles / 5sec = 4miles /sec would be the average speed for the last 20 m
Explanation:
The answer is 4 m/s.
In the first 5 seconds, a body travelled 10 meters. In the first 10 seconds of the travel, the body travelled a total of 30 meters, which means that in the last 5 seconds, it travelled 20 meters (30m + 10m).
The relation of speed (v), distance (d), and time (t) can be expressed as:
v = d/t
We need to calculate the speed of the second 5 seconds of the travel:
d = 20 m (total 30 meters - first 10 meters)
t = 5 s (time from t = 5 seconds to t = 10 seconds)
Thus:
v = 20m / 5s = 4 m/s
PLEASE GIVE BRAINIEST!! HOPE THIS HELPS
Answer:
It is 52° below the celestial equator.
Explanation:
The declination is the angle in degrees measured north (+) or south (-) of the an imaginary line called the celestial equator.
The celestial equator is a projection of the earth's equator on the celestial sphere. imaginary
The star named Canopus has a declination of approximately –52°.
Since the angle is negative, this shows that it is south or below the celestial equator and at 52° south of the celestial equator.
Thus, the star named Caponus is 52° below the celestial equator.
Answer:
a = 0.8 m/s^2
Explanation:
Force equation: F = ma
F = ma -> a = F/m = 2.8*10^3 N / 3.5*10^3 kg = 0.8 m/s^2
