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kupik [55]
3 years ago
6

What would stars be like if hydrogen had the smallest mass per nuclear particle? What would stars be like if hydrogen had the sm

allest mass per nuclear particle? Stars would be brighter. All stars would be red giants. Nuclear fusion would not occur in stars of any mass.
Physics
1 answer:
kvv77 [185]3 years ago
7 0

Answer:

Nuclear fusion would not occur in stars of any mass.

Explanation:

Stars are made of exploding balls of hydrogen and helium. Without the right amount of hydrogen, there would be no nuclear fussion.

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Mrs. Buckley asked her physical science class to look at the graph and tell which of the following explanations are most likely
iren [92.7K]

I think it's D. Options C and D are true. The graph shows an increase in speed from points 6 to 12, which means Option C is true. It shows an even bigger increase in speed from points 24 to 30, and since bikes go faster when traveling downhill, I would think that Option D was correct as well.

3 0
4 years ago
Read 2 more answers
Which statements are true for two oppositely charged, isolated parallel plates: C=capacitance, U=stored energy (Q and -Q = charg
vlada-n [284]

Answer:

Explanation:

1) True. The stored energy (U) is proportional to the electric field strength (E). The electric field strength decreases when a dielectric is introduced hence inserting a dielectric decreases U.

2) False. From the formula C=\frac{Q}{V}=\frac{Q}{Vd}, capacitance is inversely proportional to distance hence if the distance is doubled, capacitance decreases.

3) False. As the distance between the electric field and the object increases, its electric field decreases.

4) False. If a dielectric is inserted, the plates are further separated. Q stays the same.

5) True. The electric field strength decreases when a dielectric is introduced and  capacitance is inversely proportional to electric field hence Inserting a dielectric increases C

6) True. If a dielectric is inserted, the plates are further separated. Q stays the same.

7) True. When the distance is doubled, U increases

7 0
3 years ago
A car travels 140 miles in 3 hours. What is its velocity?
Maslowich

Answer:

46.67 miles/s

Explanation:

...........

3 0
3 years ago
Air enters the diffuser of a jet engine operating at steady state at 18 kPa, 216 K and a velocity of 265 m/s, all data correspon
earnstyle [38]

Answer:

45.44m/s

Explanation:

To solve this problem it is necessary to go back to the concepts related to the first law of thermodynamics,

in which it deepens on the conservation of the Energy.

The first law of Thermodynamics is given by the equation:

0 = \dot{Q}-\dot{W}+\dot{m}(h_1-h_2)+\dot{m}(\frac{V_1^2-V^2_2}{2})+\dot{m}g(z_1-z_2)

Where,

\dot{Q}= Heat transfer

\dot{W} =Work

\dot{m} =Flow mass

V_i =Velocity

h_i = Specific Enthalpy

g =Gravity

z_i =Height

From this equation we have that there is not Heat transfer, Work and changes in Height. Then,

Then our equation would be,

0=\dot{m}(h_1-h_2)+\dot{m}(\frac{V_1^2-V^2_2}{2})

Solving for V_2,

V_2 = \sqrt{V_1^2+2(h_1-h_2)}

From the tables of ideal gas (air) at 216K we have,

h_1 = 209.97+(219.97-209.97)(\frac{216-210}{220-210})

h_1 = 215.97kJ/kg

From the tables at 250K, we have that

h_2 = 250.05kJ/kg

The velocity was previously given, then

V_1 =265m/s

Replacing in the equation:

V_2 = \sqrt{265^2+2(215.97-250.05)*10^3}

V_2 = 45.44m/s

Therefore the velocity of the air at the diffuser exit is 45.44m/s

3 0
4 years ago
Which describes the rotational motion of a planet?
Ray Of Light [21]
<span>B.) The motion of the planet as it spins on its axis

Please be careful with option A, 'cause it is "Revolutionary motion", many people would choose that but, it's wrong.

In short, Your Answer would be Option B

Hope this helps!</span>
4 0
4 years ago
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