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Bond [772]
3 years ago
11

Importance of planning urban areas​

Engineering
1 answer:
SIZIF [17.4K]3 years ago
3 0

Answer:

Well, it is very important to keep Urban areas organized and avoid building failures. It can even help avoid any bad adjustments that may call accidents so it is way much more better to plan it out carefully and make sure to include correct measurements and all

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9966 [12]

Answer:

Could ask a family member to help

Explanation:

5 0
4 years ago
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The Fisher effect says that _______ . Group of answer choices the nominal interest rate adjusts one for one with the inflation r
Greeley [361]

Answer:

what wrong subject

Explanation:

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3 years ago
Number pattern Write a recursive method called print Pattern() to output the following number pattern. Given a positive integer
lilavasa [31]

Answer:

See explaination

Explanation:

Code;

import java.util.Scanner;

public class NumberPattern {

public static int x, count;

public static void printNumPattern(int num1, int num2) {

if (num1 > 0 && x == 0) {

System.out.print(num1 + " ");

count++;

printNumPattern(num1 - num2, num2);

} else {

x = 1;

if (count >= 0) {

System.out.print(num1 + " ");

count--;

if (count < 0) {

System.exit(0);

}

printNumPattern(num1 + num2, num2);

}

}

}

public static void main(String[] args) {

Scanner scnr = new Scanner(System.in);

int num1;

int num2;

num1 = scnr.nextInt();

num2 = scnr.nextInt();

printNumPattern(num1, num2);

}

}

See attachment for sample output

3 0
3 years ago
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What are primary and secondary super-heaters?
Maru [420]

Explanation:

Superheater has two types of parts which are:

  • The primary super-heater
  • The secondary super-heater

Primary super-heater is first heater which is passed by the steam after steam comes out of steam drum.

After steam is heated on super primary heater, then the steam is passed on secondary super-heater so to be heated again. Thus, on secondary super-heater, the steam formed is hottest steam among others.

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3 0
3 years ago
An electron is traveling with initial kinetic energy K in a uniform electric field. The electron comes to rest momentarily after
KIM [24]

Answer:

The answer is below

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a) The work done is equal to the loss in kinetic energy (KE)

Change in kinetic energy (ΔKE) = Final kinetic energy - initial kinetic energy

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But the final velocity is 0 (at rest). Hence:

Final KE = \frac{1}{2}mv_f^2=\frac{1}{2}m(0)^2=0

ΔKE = 0 - K = -K

W = ΔKE = -K

Also, the work done (W) = charge (q) * distance (d) * electric field intensity (E)

W = qEd

but q = -e, hence:

W = -e * E * d

Using:

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E= K / (e * d)

b) The electric field is in the direction of the electrons motion

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