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Veseljchak [2.6K]
2 years ago
11

A wheel spins at a constant angular speed of 24rad/s.How many revolutions will the dosk go through in 5minutes?​

Engineering
1 answer:
Margaret [11]2 years ago
5 0

<u>Answer:</u>

The wheel will go through 1146 revolutions in 5 minutes.

<u>Explanation:</u>

We can the formula:

\boxed{\omega = \frac{2 \pi}{T}}

where

ω ⇒ angular speed (24 rad/s),

T ⇒ time period (? s),

and solve for T to find the time it takes for the wheel to complete one revolution.

⇒  24 = \frac{2 \pi}{T}

⇒  T = \bf \frac{2 \pi}{24}  s

This means it takes \bf \frac{2 \pi}{24} seconds for the wheel to complete one revolution.

Now, using the unitary method,

In \frac{2 \pi}{24} seconds          ⇒    1 revolution completed

In 1 second              ⇒    1 ÷ \frac{2 \pi}{24}   =  \frac{24}{2 \pi}  revolutions completed

In (5 × 60 = ) 300s  ⇒     \frac{24}{2 \pi}   ×  300   = 1145.9

                                                            ≅ 1146 revolutions completed

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A gasoline engine has a piston/cylinder with 0.1 kg air at 4 MPa, 1527◦C after combustion, and this is expanded in a polytropic
Roman55 [17]

Answer:

The expansion work is 71.24 kJ and heat transfer is -16.89 kJ

Explanation:

From ideal gas law,

Initial volume (V1) = nRT/P

n is the number of moles of air in the cylinder = mass/MW = 0.1/29 = 0.00345 kgmol

R is gas constant = 8314.34 J/kgmol.K

T is initial temperature = 1527 °C = 1527+273 = 1800 K

P is initial pressure = 4 MPa = 4×10^6 Pa

V1 = 0.00345×8314.34×1800/(4×10^6) = 0.013 m^3

V2 = 10×V1 = 10×0.013 = 0.13 m^3

The process is a polytropic expansion process

polytropic exponent (n) = 1.5

P2 = P1(V1/V2)^n = 4×10^6(0.013/0.13)^1.5 = 1.26×10^5 Pa

Expansion work = (P1V1 - P2V2) ÷ (n - 1) = (4×10^6 × 0.013 - 1.26×10^5 × 0.13) ÷ (1.5 - 1) = 35620 ÷ 0.5 = 71240 J = 71240/1000 = 71.24 kJ

Heat transfer = change in internal energy + expansion work

change in internal energy (∆U) = Cv(T2 - T1)

T2 = PV/nR = 1.26×10^5 × 0.13/0.00345×8314.34 = 571 K

Cv = 20.785 kJ/kgmol.K

∆U = 20.785(571 - 1800) = -25544.765 kJ/kgmol × 0.00345 kgmol = -88.13 kJ

Heat transfer = -88.13 + 71.24 = -16.89 kJ

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a.) -147V

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c.) Same process as part b. Draw out the circuit and you'll see that the potential a point V_N is the same as the voltage across V_NP added with the 2V from the other box.

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Answer:

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