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nexus9112 [7]
4 years ago
12

In a device called the ballistic pendulum, a compressed spring is used to launch a steel ball horizontally into a soft target ha

nging from a string. The ball embeds in the target and the two swing together from the string. Describe the energy transfers and/or transformations that take place during the use of the ballistic pendulum and at what points they occur
Physics
1 answer:
N76 [4]4 years ago
5 0

Answer:

When the spring in the ballistic pendulum is compressed, <em>energy is stored up in the spring as potential energy. </em>When the steel ball is launched by the spring, <em>the stored up potential energy of the compressed spring is transformed and transferred into the kinetic energy of the steel ball as it flies off to hit its target. </em>On hitting the soft target, <em>some of the kinetic energy of the steel ball is transferred to the soft target (since they stick together), and they both start to swing together</em>. During the process of swinging, the system's energy is transformed between kinetic and potential energy. <em>At the maximum  displacement of the ball from its point of rest, all the energy is converted to potential energy of the system</em>. <em>At the lowest point of travel (at the rest point), all the energy of the system is transformed into kinetic energy. </em>In between these two points, <em>energy the energy of the system is a combination of both kinetic and potential energy.</em>

In the end, all the energy will be transformed and lost as heat to the surrounding; due to the air resistance around; bringing the system to a halt.

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Answer:

α = -π/3 rad/s²

θ = 1.5π rad ≈ 4.71 rad

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Explanation:

30 rev/min (2π rad/rev) / (60 s/min) = π rad/s

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θ = ½αt² = ½(π/3)3² = 1.5π rad ≈ 4.71 rad

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3 years ago
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It's difficult because the temperature is obviously maintained well if it's designated a specific heat.
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4 years ago
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Answer:

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Explanation:

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7 0
3 years ago
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Question 2 Ammonium phosphate NH43PO4 is an important ingredient in many fertilizers. It can be made by reacting phosphoric acid
Mama L [17]

Answer:

The answer is 12.27 g (NH4)3PO4

Explanation:

Step 1: balance the chemical equation:

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step 2: the molar masses of each of the reagents and products are calculated using the periodic table:

H3PO4:

3 atoms of H: 3x1=3 g/mol

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4 atoms of O: 4x16=64 g/mol

Molar mass=3+30.97+64=97.97 g/mol

3NH3:

3 atoms of N: 3x14=42 g/mol

9 atoms of H: 9x1=9 g/mol

Molar mass=42+9=51 g/mol

(NH4)3PO4:

3 atoms of N: 3x14=42 g/mol

12 atoms of H: 12x1=12 g/mol

1 atom of P: 1x30.97=30.97 g/mol

4 atoms of O: 4x16=64 g/mol

Molar mass=42+12+30.97+64=148.97 g/mol

we make a rule of three to calculate the amount of ammonium phosphate:

51 g NH3------------------148.97 g (NH4)3PO4

4.2 g NH3-----------------x g (NH4)3PO4

Clearing the x, we have:

x g (NH4)3PO4 = \frac{(4.2 g NH3)x(148.97 g (NH4)3PO4)}{51 g NH3}=12.27 g (NH4)3PO4

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4 years ago
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