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ASHA 777 [7]
3 years ago
12

'Suppose your hand moves upward by 0.50m while you are throwing the ball. The ball leaves your hand with an upward velocity of 2

0.0 m/s. Find the magnitude of the force (assumed constant) that your hand exerts on the ball. Ignore air resistance.' Now my question is not 'What is the magnitude' but rather: why did I get (roughly) the same answer using F=ma when you were supposed to use the total mechanical energy (W+K1+U1=K2+U2). So I'm more confused about how the 2 formulas are 'related', what the force actually represents in both, when to use what and if there is an actual difference.

Physics
1 answer:
Mademuasel [1]3 years ago
4 0

The definition of acceleration  allows us to find the results for the questions about the relationship between force and energy:

  • The forces is relationship to kinetic and potential energy through the work it can do.
  • Energy concepts are easier to use because they are scalar.

<h3>Newton's second law.</h3><h3 />

Newton's second law gives a relationship between force, mass and acceleration of bodies.

             F = ma

Where F is the force, m is the mass, and a is the acceleration.

From kinematics the acceleration is defined by

           a =\frac{dv}{dt}  

If we use the chain rule.

          a = \frac{dv}{dx} \frac{dx}{dt}

         a= v  \frac{dv}{dx}

We substitute

           F = \frac{dv}{dx}  

           ∫  F dx = m ∫ v dv

          ∫ F dx = ½ m v²

The term on the right is kinetic energy, therefore force and kinetic energy are related, but it is easier to use energy because it is a scalar since force is a vector quantity, it has three components.

Work is defined by the dot product of force times distance.

           W = ∫ F . d x

If we assume a system moving at constant speed, the upward force is equal to the weight of the body.

           F= W= mg

Let's substitute.

            W = m g h

The term is potential energy, therefore potential energy is equal to work and is directly related to the applied force.

In general, the concepts of energy are used when we want the result at a specific point and Newton's second law is used when we want the result at all points.

In conclusion using the definition of acceleration in kinematics we can find the results for the questions the relationship of force and energy are:

  • The forces this relationship to kinetic and potential energy through the work it can do.
  • Energy concepts are easier to use because they are scalar.

Learn more gives force and energy here: brainly.in/question/4177014

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Hi, what is it you need help with?

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3) What is the weight of an object with a mass of 5.2 kilograms?​
inna [77]

Answer:

50.96 N

Explanation:

weight = mass x gravity

We know that gravity = 9.8 m/s^2 and mass = 5.2 kg.

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8 0
3 years ago
A circular loop of flexible iron wire has an initial circumference of 164cm , but its circumference is decreasing at a constant
Travka [436]

Answer:

emf = 0.02525 V

induced current with a counterclockwise direction

Explanation:

The emf is given by the following formula:

emf=-\frac{\Delta \Phi_B}{\Delta t}=-B\frac{\Delta A}{\Delta t}\ \ =-B\frac{A_2-A_1}{t_2-t_1}   (1)

ФB: magnetic flux =  BA

B: magnitude of the magnetic field = 1.00T

A2: final area of the loop; A1: initial area

t2: final time, t1: initial time

You first calculate the final A2, by taking into account that the circumference of loop decreases at 11.0cm/s.

In t = 4 s the final circumference will be:

c_2=c_1-(11.0cm/s)t=164cm-(11.0cm/s)(4s)=120cm

To find the areas A1 and A2 you calculate the radius:

r_1=\frac{164cm}{2\pi}=26.101cm\\\\r_2=\frac{120cm}{2\pi}=19.098cm

r1 = 0.261 m

r2 = 0.190 m

Then, the areas A1 and A2 are:

A_1=\pi r_1^2=\pi (0.261m)^2=0.214m^2\\\\A_2=\pi r_2^2=\pi (0.190m)^2=0.113m^2

Finally, the emf induced, by using the equation (1), is:

emf=-(1.00T)\frac{(0.113m^2)-(0.214m^2)}{4s-0s}=0.0252V=25.25mV

The induced current has counterclockwise direction, because the induced magneitc field generated by the induced current must be opposite to the constant magnetic field B.

4 0
3 years ago
The Burj Khalifa is the tallest building in the world at 828 m. How much work would a man with a weight of 700 N do if he climbe
8090 [49]

Answer:

579600J

Explanation:

Given parameters:

Height of the building  = 828m

Weight of the man  = 700N

Unknown:

Work done by the man  = ?

Solution:

The work done by the man is the same as the potential energy expended.

Work done:

            Work done  = Weight x height  = 700 x 828

       Work done  = 579600J

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