Answer:
60
Step-by-step explanation:
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:

And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Answer: 127^9 so 8594754748609400000
Step-by-step explanation: i’m not sure but 4+6 (7x3)-3 = 127 127^9
the value of c that makes the expression a perfect square binomial is c=4 .
<u>Step-by-step explanation:</u>
Here we have , an expression x2 + 4x + c or ,
. We need to find the value of c that makes the expression a perfect square binomial. Let's find out:
We have , 
⇒ 
⇒ 
Now , we know that 
Comparing above equation , to
we get ;
⇒
{
}
⇒ 
⇒ 
Therefore , the value of c that makes the expression a perfect square binomial is c=4 .
The area is the sum of 'n' rectangle areas.
The width of the rectangle is size of interval, (domain size)/n
The height of each rectangle is f(interval) as interval moves along domain.
For this example, domain size = 3-1 = 2
size of interval = 2/n
height varies from f(1) to f(3), increasing by 2/n each time.
f(1+(2/n)i)
Putting this together, the area is the sum of:

Since you are given the function f(x). Sub input into f(x) to get area in terms of n and i.

Finally, the summation is: