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olga2289 [7]
3 years ago
7

The Steamboat Geyser in Yellowstone National Park shoots water into the air at 48.0 m/s. How

Physics
2 answers:
qwelly [4]3 years ago
7 0

Answer:

The maximum height reached by the water is 117.55 m.

Explanation:

Given;

initial velocity of the water, u = 48 m/s

at maximum height the final velocity will be zero, v = 0

the water is going upwards, i.e in the negative direction of gravity, g = -9.8 m/s².

The maximum height reached by the water is calculated as follows;

v² = u² + 2gh

where;

h is the maximum height reached by the water

0 = u² + 2gh

0 = (48)² + ( 2 x -9.8 x h)

0 = 2304 - 19.6h

19.6h = 2304

h = 2304 / 19.6

h = 117.55 m

Therefore, the maximum height reached by the water is 117.55 m.

Anon25 [30]3 years ago
4 0

Answer:

The maximum height reached by the water is 117.55 m.

Explanation:

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QiC S A particle of mass m moves along a straight line with constant velocity v→ in the x direction, a distance b from the x axi
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Does the particle possess any angular momentum about the origin?

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To learn more about mass, refer to:

brainly.com/question/3187640

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7 0
2 years ago
[ b) The time of reverberation of an empty hall without and with 500 audiences is 1.5 sec and 1.4 sec respectively. Find the rev
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<h3>Reverberation time with 800 audience</h3>

R₁V₁ = R₂V₂

where;

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