Option 3.
Neptune Uranus Saturn Jupiter Mars Earth Venus Mercury.
'Displacement' is the distance and direction between the starting point and
ending point, regardless of the path followed to get there.
A particle that's executing simple harmonic motion is always in the same place
where it was one time period ago, and where it will be later after another time
period has passed.
So its displacement during exactly one time period is exactly zero.
Answer:
Explanation:
Given:
Final force between them=17(initial force between them)
initial separation between them 
Final separation between them 
Let Q and q be the charges on them then
According to newton's third law: every action has an equal and opposite reaction, so yes the ground does move backwards. You have 4 forces acting on you at any given time: pushing force, friction force, gravity, and normal force. you push against something to propel forward, you have to overcome gravity and friction, and normal force keeps things upright to prevent them from falling into each other.
<span>If everything is motionless at every instant, and time is entirely composed of instants, then motion is impossible, so it must be an illusion.
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if you really want things to get confusing you can read up on zeno's dichotomy paradox stating that there is infinate amount of times you can divide something such as a distance traveled over time and you will stil
Complete question:
Seat belts and air bags save lives by reducing the forces exerted on the driver and passengers in an automobile collision. Cars are designed with a "crumple zone" in the front of the car. In the event of an impact, the passenger compartment decelerates over a distance of about 1 m as the front of the car crumples. An occupant restrained by seat belts and air bags decelerates with the car. In contrast, a passenger not wearing a seat belt or using an air bag decelerates over a distance of 5mm.
(a) A 60 kg person is in a head-on collision. The car's speed at impact is 15 m/s . Estimate the net force on the person if he or she is wearing a seat belt and if the air bag deploys.
Answer:
The net force on the person as the air bad deploys is -6750 N backwards
Explanation:
Given;
mass of the passenger, m = 60 kg
velocity of the car at impact, u = 15 m/s
final velocity of the car after impact, v = 0
distance moved as the front of the car crumples, s = 1 m
First, calculate the acceleration of the car at impact;
v² = u² + 2as
0² = 15² + (2 x 1)a
0 = 225 + 2a
2a = -225
a = -225 / 2
a = -112.5 m/s²
The net force on the person;
F = ma
F = 60 (-112.5)
F = -6750 N backwards
Therefore, the net force on the person as the air bad deploys is -6750 N backwards
