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dexar [7]
3 years ago
15

A 120-V electrical line in a home is connected to a 100-W lightbulb, a 180-W television set, a 230-W desktop computer, a 1050-W

toaster, and a 240-W refrigerator.
How much current is flowing in the line?

Express your answer with the appropriate units.
Physics
1 answer:
Natasha_Volkova [10]3 years ago
5 0

Answer:

Therefore,

15 Ampere current is flowing in the line.

Explanation:

Given:

Voltage, V = 120 V

Power of Appliances,

P1 = 100-W lightbulb,

P2 = 180-W television set,

P3 = 230-W desktop computer,

P4 =  1050-W toaster, and

P5 = 240-W refrigerator.

To Find:

Current  flowing in the line, I = ?

Solution:

We have Power formula,

Power=Voltage\times Current\\P=V\times I

For Household Voltage Remain Same and Current will differ and there will be a Parallel Connection for the Appliances,

Therefore,

1 .For lightbulb,

P_{1}=V\times I_{1}

Substituting the values we get

100 = 120\times I_{1}\\I_{1}=0.8333\ Ampere

2. Similarly for television,

P_{2}=V\times I_{2}

Substituting the values we get

180= 120\times I_{2}\\I_{2}=1.5\ Ampere

3. Similarly for desktop computer,

P_{3}=V\times I_{3}

Substituting the values we get

230= 120\times I_{3}\\I_{3}=1.9166\ Ampere

4. Similarly for toaster,

P_{4}=V\times I_{4}

Substituting the values we get

1050= 120\times I_{4}\\I_{4}=8.75\ Ampere

5. Similarly for refrigerator,

P_{5}=V\times I_{5}

Substituting the values we get

240= 120\times I_{5}\\I_{5}=2\ Ampere

In Parallel connection Total current 'I' is given as,

I=I_{1}+I_{2}+I_{3}+I_{4}+I_{5}

Substituting the values we get

I=0.8333+1.5+1.9166+8.75+2=14.9999\approx 15\ Ampere

Therefore,

15 Ampere current is flowing in the line.

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4 0
2 years ago
An inventor claims to have invented a heat engine that receives 750kJ of heat from a source at 400K and produces 250kJ of net wo
IRISSAK [1]

Answer:

the claim is not valid or reasonable.

Explanation:

In order to test the claim we will find the maximum and actual efficiencies. maximum efficiency of a heat engine can be found as:

η(max) = 1 - T₁/T₂

where,

η(max) = maximum efficiency = ?

T₁ = Sink Temperature = 300 K

T₂ = Source Temperature = 400 K

Therefore,

η(max) = 1 - 300 K/400 K

η(max) = 0.25 = 25%

Now, we calculate the actual frequency of the engine:

η = W/Q

where,

W = Net Work = 250 KJ

Q = Heat Received = 750 KJ

Therefore,

η = 250 KJ/750 KJ

η = 0.333 = 33.3 %

η > η(max)

The actual efficiency of a heat engine can never be greater than its Carnot efficiency or the maximum efficiency.

<u>Therefore, the claim is not valid or reasonable.</u>

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3 years ago
How much have jellyfish populated since 2015?
My name is Ann [436]
About a mil sience 2014-2015
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A complete circuit is often referred to as a(n) _______ circuit
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Answer:

Complete Circuit

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3 years ago
An Ethernet cable is 4.00m long. The cable has a mass of 0.200kg . A transverse pulse is produced by plucking one end of the tau
Mashcka [7]

Based on the length of the Ethernet cable and the mass, the tension in the cable can be found to be 80 N.

<h3>How much tension is in the cable?</h3>

The tension in the cable can be found as:

= 4 x mass x length x frequency

Solving for the frequency is:

= 1 / (0.800 / 4)

= 1 / 0.20

= 5.0 Hz

The tension is therefore:

= 4 x 0.20 x 4.00 x 5

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