Answer:
a) g1 = 8.467 10⁻¹⁴ m / s²
, b) g2 = 5.65 10⁻¹⁰ m / s²
, c) g2 / g1 = 6.6 10³
Explanation:
a) for this we will use Newton's second law where force is the force of universal gravitation
F = m a
G m M / r² = m a
a = g = G M / r²
By the effect of Pluto
g1 = 6.67 10⁻¹¹ 1.3 10²² / (3.2 10¹²)²
g1 = 8.467 10⁻¹⁴ m / s²
b) By the effect of Uranus
g2 = 6.67 10⁻¹¹ 8.68 10²⁵ / (3.2 10¹²)²
g2 = 5.65 10⁻¹⁰ m / s²
c) the relationship between these accelerations
g2 / g1 = 5.65 10⁻¹⁰ / 8.47 10⁻¹⁴
g2 / g1 = 0.66 10⁴
g2 / g1 = 6.6 10³
Answer:
yes, kinda like when babies are made, there is friction
Explanation:
Your position at time
, relative to the stop line:

The Porsche's position:

a. You pass the Porsche immediately after the time it takes for
:

at which point you both will have traveled 7.8 m from the stop line.
b. The equation in part (a) has two solutions. The Porsche passes you at the second solution of about
, at which point you both will have traveled 29 m.
c. At time
, the Porsche is moving at velocity

so that at the moment it passes you, its speed is 13 m/s, which is about 46.8 km/h and below the speed limit, so neither of you will be pulled over.
The correct answer is
"As the distance from the earth increases, the gravitational pull on the spaceship would decrease."
In fact, the gravitational force (attractive) exerted by the Earth on the spaceship is given by

where G is the gravitational constant, M the Earth's mass, m the mass of the spaceship and d the distance of the spaceship from the Earth. As we can see from the formula, as the distance d between the spaceship and the Earth increases, the gravitational force F decreases, so answer D) is the correct one.
The diameter of the wire is 2.8 * 10^-3 m.
<h3>What is the length?</h3>
Mass of the wire = 1.0 g or 1 * 10^-3 Kg
Resistance = 0.5 ohm
Resistivity of copper = 1.7 * 10^-8 ohm meter
Density of copper = 8.92 * 10^3 Kg/m^3
V = m/d
But v = Al
Al = m/d
A = m/ld
Resistance = ρl/A
= ρl/m/ld =
l^2 = Rm/ρd
l = √ Rm/ρd
l = √0.5 * 1 * 10^-3 / 1.7 * 10^-8 * 8.92 * 10^3
l = 1.82 m
A = πr^2
Also;
A = m/ld
A = 1 * 10^-3 Kg / 1.82 m * 8.92 * 10^3 Kg/m^3
A = 6.2 * 10^-5 m^2
r^2 = A/ π
r = √A/ π
r = √6.2 * 10^-5 m^2/3.142
r = 1.4 * 10^-3 m
Diameter = 2r = 2( 1.4 * 10^-3 m) = 2.8 * 10^-3 m
Learn more about resistivity:brainly.com/question/14547003
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Missing parts;
Suppose you wish to fabricate a uniform wire from 1.00g of copper. If the wire is to have a resistance of R=0.500Ω and all the copper is to be used, what must be (a) the length and (b) the diameter of this wire?