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aliya0001 [1]
3 years ago
9

If 2.0 j of work Is done raising a 180 g Apple how far was it lifted

Physics
1 answer:
andrew11 [14]3 years ago
6 0

The apple is lifted by 1.1 m

<u>Explanation</u>:

  • Given that, mgh = 2 J and mass of apple = 180g
  • Step 1: convert grams to kg as work is given in SI units.

                    180 g = 0.18 kg

  • Step 2: substitute in the formula for work done.

                    0.18 * 10 * h = 2

  • Step 3: calculate the value of h from this formula.

                      h = 2/1.8

                      h = 1.11 m

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Answer:

a) g1 = 8.467 10⁻¹⁴ m / s² , b)  g2 = 5.65 10⁻¹⁰ m / s² , c) g2 / g1 = 6.6 10³

Explanation:

a) for this we will use Newton's second law where force is the force of universal gravitation

         F = m a

        G m M / r² = m a

        a = g = G M / r²

By the effect of Pluto

        g1 = 6.67 10⁻¹¹  1.3 10²² / (3.2 10¹²)²

        g1 = 8.467 10⁻¹⁴ m / s²

b) By the effect of Uranus

        g2 = 6.67 10⁻¹¹ 8.68 10²⁵ / (3.2 10¹²)²

        g2 = 5.65 10⁻¹⁰ m / s²

c) the relationship between these accelerations

        g2 / g1 = 5.65 10⁻¹⁰ / 8.47 10⁻¹⁴

        g2 / g1 = 0.66 10⁴

        g2 / g1 = 6.6 10³

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3 years ago
Friction occurs when the and of two surfaces stick to each other
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Explanation:

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You’re driving your car towards an intersection. A Porsche is stopped at the red light. You’re traveling at 36 km/h (10 m/s). As
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Your position at time t, relative to the stop line:

x_1=-15\,\mathrm m+\left(10\dfrac{\rm m}{\rm s}\right)t

The Porsche's position:

x_2=\dfrac12\left(3\dfrac{\rm m}{\mathrm s^2}\right)t^2

a. You pass the Porsche immediately after the time it takes for x_1=x_2:

-15\,\mathrm m+\left(10\dfrac{\rm m}{\rm s}\right)t=\dfrac12\left(3\dfrac{\rm m}{\mathrm s^2}\right)t^2\implies t=2.3\,\rm s

at which point you both will have traveled 7.8 m from the stop line.

b. The equation in part (a) has two solutions. The Porsche passes you at the second solution of about t=4.4\,\rm s, at which point you both will have traveled 29 m.

c. At time t, the Porsche is moving at velocity

v=\left(3\dfrac{\rm m}{\mathrm s^2}\right)t

so that at the moment it passes you, its speed is 13 m/s, which is about 46.8 km/h and below the speed limit, so neither of you will be pulled over.

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A spaceship orbiting earth flies to the moon. How is the gravitational force pulling on the spaceship related to the distance th
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The correct answer is "As the distance from the earth increases, the gravitational pull on the spaceship would decrease."

In fact, the gravitational force (attractive) exerted by the Earth on the spaceship is given by
F=G \frac{Mm}{d^2}
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3 years ago
S Suppose you wish to fabricate a uniform wire from a mass m of a metal with density rhom and resistivity rho. If the wire is to
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The diameter of the wire is 2.8 * 10^-3 m.

<h3>What is the length?</h3>

Mass of the wire = 1.0 g or 1 * 10^-3 Kg

Resistance = 0.5 ohm

Resistivity of copper = 1.7 * 10^-8 ohm meter

Density of copper = 8.92 * 10^3 Kg/m^3

V = m/d

But v = Al

Al = m/d

A = m/ld

Resistance = ρl/A

= ρl/m/ld =

l^2 = Rm/ρd

l = √ Rm/ρd

l = √0.5 * 1 * 10^-3 / 1.7 * 10^-8 * 8.92 * 10^3

l = 1.82 m

A = πr^2

Also;

A = m/ld

A = 1 * 10^-3 Kg / 1.82 m * 8.92 * 10^3 Kg/m^3

A = 6.2 * 10^-5 m^2

r^2 = A/ π

r = √A/ π

r = √6.2 * 10^-5 m^2/3.142

r = 1.4 * 10^-3 m

Diameter = 2r = 2( 1.4 * 10^-3 m) = 2.8 * 10^-3 m

Learn more about resistivity:brainly.com/question/14547003

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Missing parts;

Suppose you wish to fabricate a uniform wire from 1.00g of copper. If the wire is to have a resistance of R=0.500Ω and all the copper is to be used, what must be (a) the length and (b) the diameter of this wire?

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1 year ago
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