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3 years ago

6

Hannah suffered a brain injury, which left her remote memory relatively intact. However, she is unable to process new informatio

n that can be stored for later retrieval. Hannah's impairment is called __________.

1 answer:

qaws [65]3 years ago

6 0

Answer:

extensive bilateral damage

Explanation:

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Name the manufacturing process that the worker is using to create the workpiece. The manufacturing process carried out by the bl

krok68 [10]

Answer:

Metamorphic manufacturing

Explanation:

I don't know what form of an answer you wanted but I hope this helps :)

7 0

3 years ago

(a) For BCC iron, calculate the diameter of the minimum space available in an octahedral site at the center of the (010) plane,

Romashka-Z-Leto [24]

Answer:

a) diameter available = 0.0384 nm

b)The space is smaller than the carbon atom which has a radius of 0.077 nm and this simply means that the carbon atom will not conquer these sites

Explanation:

For BCC iron

From Appendix B given,select the lattice parameter ( a ) as = 0.2866 nm

The BCC iron has 4 atomic radii and therefore the body diagonal length = $a(3)^\frac{1}{2}$

expressing the atomic radius of the BCC iron

4r = $a(3)^\frac{1}{2}$

insert the value of (a) from appendix B which is = 0.2866 nm

4r = $0.2866 nm (3)^\frac{1}{2}$

therefore r = 0.4964 nm / 4 = 0.1241 nm

Refer again to appendix C given select the atomic radius of the BCC iron as = 0.1241 nm assuming the atomic radius of the iron are the same

then the radius ratio = 0.62

Refer to the Figure 3.2 given, the amount of space required for an interstitial at the BCC position is between the atoms at the FCC position and also in this space there are two atoms that are equal to a radius of 0.2482 nm

The diameter of the minimum space available

$d_{a} = a - r_{a}$

$r_{a} = atomic radii$ = 0.2482 nm

a = 0.2666 nm

therefore

d $_{a}$ = 0.2866 nm - 0.2482 nm = 0.0384 nm

comparing this to the diameter of a carbon atom

The space is smaller than the carbon atom which has a radius of 0.077 nm and this simply means that the carbon atom will not conquer these sites

7 0

3 years ago

Which of the following describes what a manufacturing engineer does

oksian1 [2.3K]

Manufacturing Engineers focus on the design and operation of integrated systems for the production of high-quality, economically competitive products.

7 0

3 years ago

Read 2 more answers

A specimen of a 4340 steel alloy with a plane strain fracture toughness of 54.8 MPa (50 ksi ) is exposed to a stress of 2023 MPa

Neko [114]

Answer:

Explanation:

The formula for critical stress is

$\sigma_c=\frac{K}{Y\sqrt{\pi a} }$

$\sigma_c =\texttt{critical stress}$

K is the plane strain fracture toughness

Y is dimensionless parameters

We are to Determine the Critical stress

Now replacing the critical stress with 54.8

a with 0.2mm = 0.2 x 10⁻³

Y with 1

$\sigma_c=\frac{54.8}{1\sqrt{\pi \times 0.2\times10^{-3}} } \\\\=\frac{54.8}{\sqrt{6.283\times10^{-4}} } \\\\=\frac{54.8}{0.025} \\\\=2186.20Mpa$

The fracture will not occur because this material can handle a stress of 2186.20Mpa before fracture. it is obvious that is greater than 2023Mpa

Therefore, the specimen does not failure for surface crack of 0.2mm

4 0

3 years ago

1. A soil core sampling tube of 4 cm diameter, 12 cm length and initial mass of 0.525 kg (sample only), was dried at 105o C and

belka [17]

Answer:

porosity = 0.07 or 7%

dry bulk density = 3.25g/cm3]

water content =

Explanation:

bulk density = dry Mass / volume of sample

dry mass = 0.490kg = 490g

volume = πr2h = 3.142 * 2 *2 *12 = 150.8cm3

density = 490/150.8 = 3.25g/cm3

porosity = $\frac{wet mass - dry mass }{wet mass}$ = $\frac{0.525 - 0.49}{0.525}$ = 0.07 or 7%

water content = $\frac{wet mass - dry mass}{wet mass}$ = 7%

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4 years ago

Read 2 more answers