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Art [367]
1 year ago
14

iron ball weight 400 gram inside water when it is completely impressed in water 53 gram water is displaced what will be the weig

ht of iron ball in air?​
Physics
1 answer:
Alika [10]1 year ago
8 0

Answer:

453 gm

Explanation:

<u>Immersed </u>objects are buoyed up by force equal to mass of displaced liquid

400 + 53 = 453 gm  in air

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A flat metal washer is heated. As the washer's temperature increases, what happens to the hole in the center? A flat metal washe
STALIN [3.7K]

To solve this exercise it is necessary to take into account the concepts related to thermal expansion.

The thermal expansion is given by the function,

\Delta L = L_0 \alpha \Delta T

Where,

\Delta L= Change in Length

\Delta T =Change in Temperature

\alpha =Coeficiente de dilatación lineal

L_0 = Initial Length

By quickly deducing the formula, we can realize that the greater the change in temperature, the greater the change in the length of the radius.

The change in length is proportional to the change in temperature. Considering that the other two terms are constant we have that the correct one would be: <em>The hole in the center of the washer will expand.</em>

4 0
3 years ago
A 1.5 kg bird is gliding at a height of 12 m with a speed of 3.8m/s. What is the kinetic energy of the bird, to the nearest joul
Georgia [21]

A 1.5 kg bird is gliding at a height of 12 m with a speed of 3.8m/s. The kinetic energy of the bird is 10.83 joules.

Explanation:

Kinetic energy can be defined as,The kinetic energy (KE) of an object is the energy that the object possesses due to its motion.

The Kinetic energy can be calculated by using formula,

Kinetic Energy: KE = 1/2 (mv 2)

Where, m = Mass, v = Velocity.

Here in this case the bird mass is 1.5kg and is gliding with velocity 3.8m/s

hence, KE= 1/2*(1.5)×(3.8)^2

                   =0.5×1.5×3.8×3.8

                   =10.83Joules

                   

                   

5 0
2 years ago
Which of the following is a chemical change
alina1380 [7]
What are the options u can't say that and expect me to know wat u talkin bout
5 0
3 years ago
Read 2 more answers
An electron (q=-1.602×10-19C) is placed .03m away from spherical object with a net charge of -7.2 C.
vovangra [49]

Answer:

Explanation:

electric field at the location of electron

= 9 x 10⁹ x 7.2 / .03²

= 72 x 10¹² N/C

force on electron = electric field x charge on electron

= 72 x 10¹² x 1.6 x 10⁻¹⁹

= 115.2 x 10⁻⁷ N .

C )

work done = charge on electron x potential difference at two points

potential at .03 m

= 9 x 10⁹ x 7.2 / .03

= 2.16 x 10¹² V

potential at .001 m

= 9 x 10⁹ x 7.2 / .001

= 64.8 x 10¹² V

potential difference = (64.8 - 2.16 )x 10¹² V

= 62.64 x 10¹² V  .

work done = 62.64 x 10¹² x 1.6 x 10⁻¹⁹

= 100.224 x 10⁻⁷ J .

D )

There will be no change in the magnitude of force on positron except that the direction of force will be reversed . In case of electron , there will be repulsion and in case of positron , there will be attraction .

Work done in case of electron will be positive and work done in case of positron will be negative .

electric field due to charge will be same in both the cases .

8 0
2 years ago
PLEASE HELP WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!
konstantin123 [22]
.
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3 0 0 k m
7 0
2 years ago
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