Answer:
Explanation:
A common theory suggests that desert pavements are formed through gradual removal of sand and other fine particles by the wind and intermittent rains leaving behind the large fragments. The larger rock particles are shaken into place by actions of different agents such as rain, wind, gravity, and animals
Explanation:
We know that that the range of the ball on the earth

therefore, range of the ball on moon


therefore,

Therefore, the range of ball will be 6 times on the moon than that on earth
Answer:
hope it helps
Explanation:
Newtons third law is that objects exert equal and opposite forces on each other.
'every action has an equal and opposite reaction'.
Radius of circle of spiral path = 6 m
Time period = 5 s
So the total length of the path = 



time taken by bird to cover the distance = 5 s
so the speed of the bird = distance / time



so the tangential speed in horizontal direction = 7.54 m/s
vertical velocity by which it is rising upwards = 3 m/s
so the angle with the horizontal for net speed is given as



so velocity vector will make 21.7 degree with the horizontal