Answer:
E=0.036 V/m
Explanation:
Given that
Resistivity ,ρ=2.44 x 10⁻⁸ ohms.m
d= 0.9 mm
L= 14 cm
I = 940 m A = 0.94 A
We know that electric field E
E= V/L
V= I R
R=ρL/A
So we can say that
E= ρI/A
Now by putting the values
![E=\dfrac{ 2.44\times 10^{-8}\times 0.94}{\dfrac{\pi}{4}(0.9\times 10^{-3})^2}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B%202.44%5Ctimes%2010%5E%7B-8%7D%5Ctimes%200.94%7D%7B%5Cdfrac%7B%5Cpi%7D%7B4%7D%280.9%5Ctimes%2010%5E%7B-3%7D%29%5E2%7D)
E=0.036 V/m
Answer:
Buttery popcorn contained in a large 1 liter bowl has a mass of about 50 mg and about 650 calories.
Explanation:
Liter is the most appropriate unit to measure a bowl. Usually 1 liter of liquid has a mass of 1000 gram. Since popcorn is something lightweight and only a few can fill the bowl quickly so 50 mg makes perfect sense with 1 liter of bowl and 650 calories in buttery popcorn.
Quantum numbers<span> allow us to both simplify and dig deeper into electron configurations. Electron configurations allow us to identify energy level, subshell, and the number of electrons in those locations. If you choose to go a bit further, you can also add in x,y, or z subscripts to describe the exact orbital of those subshells (for example </span><span>2<span>px</span></span>). Simply put, electron configurations are more focused on location of electrons then anything else.
<span>
Quantum numbers allow us to dig deeper into the electron configurations by allowing us to focus on electrons' quantum nature. This includes such properties as principle energy (size) (n), magnitude of angular momentum (shape) (l), orientation in space (m), and the spinning nature of the electron. In terms of connecting quantum numbers back to electron configurations, n is related to the energy level, l is related to the subshell, m is related to the orbital, and s is due to Pauli Exclusion Principle.</span>
They can either cancel each other or add up to a resultant force with a certain direction and modulus.
Newton's second law states that F=m*a, where F is the resultant force, ie ΣF.
Answer:![8.76\times 10^{-3} min^{-1}](https://tex.z-dn.net/?f=8.76%5Ctimes%2010%5E%7B-3%7D%20min%5E%7B-1%7D)
Explanation:
Given
n=5
0.3 fraction recrystallize after 100 min
According to Avrami equation
![y=1-e^{-kt^n}](https://tex.z-dn.net/?f=y%3D1-e%5E%7B-kt%5En%7D)
where y=fraction Transformed
k=constant
t=time
![0.3=1-e^{-k(100)^5}](https://tex.z-dn.net/?f=0.3%3D1-e%5E%7B-k%28100%29%5E5%7D%20)
![e^{-k(100)^5} =0.7](https://tex.z-dn.net/?f=e%5E%7B-k%28100%29%5E5%7D%20%3D0.7)
Taking log both sides
![-k\cdot (10^{10}=\ln 0.7](https://tex.z-dn.net/?f=-k%5Ccdot%20%2810%5E%7B10%7D%3D%5Cln%200.7)
![k=3.566\times 10^{-11}](https://tex.z-dn.net/?f=k%3D3.566%5Ctimes%2010%5E%7B-11%7D)
At this Point we want to compute ![t_{0.5}\ i.e.\ y=0.5](https://tex.z-dn.net/?f=t_%7B0.5%7D%5C%20i.e.%5C%20y%3D0.5)
![0.5=1-e^{-kt^n}](https://tex.z-dn.net/?f=0.5%3D1-e%5E%7B-kt%5En%7D)
![0.5=e^{-kt^n}](https://tex.z-dn.net/?f=0.5%3De%5E%7B-kt%5En%7D)
![0.5=e^{-3.566\times 10^{-11}\cdot (t)^5}](https://tex.z-dn.net/?f=0.5%3De%5E%7B-3.566%5Ctimes%2010%5E%7B-11%7D%5Ccdot%20%28t%29%5E5%7D)
taking log both sides
![\ln 0.5=-3.566\times 10^{-11}\cdot (t)^5](https://tex.z-dn.net/?f=%5Cln%200.5%3D-3.566%5Ctimes%2010%5E%7B-11%7D%5Ccdot%20%28t%29%5E5)
![t^5=1.943\times 10^{10}](https://tex.z-dn.net/?f=t%5E5%3D1.943%5Ctimes%2010%5E%7B10%7D)
![t=114.2 min](https://tex.z-dn.net/?f=t%3D114.2%20min)
Rate of Re crystallization at this temperature
![t^{-1}=8.76\times 10^{-3} min^{-1}](https://tex.z-dn.net/?f=t%5E%7B-1%7D%3D8.76%5Ctimes%2010%5E%7B-3%7D%20min%5E%7B-1%7D)