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Thepotemich [5.8K]
3 years ago
11

Make the following conversion.

Physics
2 answers:
Vesna [10]3 years ago
8 0

Answer:

The answer would be D 56,320

Explanation:

blsea [12.9K]3 years ago
7 0

Answer: 56320

Explanation:

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A suspension bridge has twin towers that are 1300 feet apart. Each tower extends 180 feet above the road surface. The cables are
zhannawk [14.2K]

Answer:

y = 17.04 ft

Explanation:

Since the cable touches the road at the mid point of two towers

so here we have vertex at that mid point taken to be origin

now the maximum height on the either side is given as

y = 180 ft

horizontal distance of the tower from mid point is given as

x = \frac{1300}{2} = 650 ft

now from the equation of parabola we have

y = k x^2

180 = k(650^2)

k = 4.26 \times 10^{-4}

now we have

y = (4.26 \times 10^{-4})x^2

now we need to find the height at distance of 200 ft from center

so we have

y = (4.26 \times 10^{-4})(200^2)

y = 17.04 ft

8 0
3 years ago
A stretched string is 2.11 m long and has a mass of 19.5 g. When the string is oscillated at 440 Hz, which is the frequency of t
Katarina [22]

Answer:

efsfefsfsdf

Explanation:

efsfesef

7 0
3 years ago
Which test was conducted on the skin found under the victim’s nails?
BARSIC [14]
Y-STR analysis. It is a DNA test used to compute and match with the possibility via lap.
5 0
3 years ago
Read 2 more answers
If the velocity of a car is 45 km/h west, how far can it travel in 0.5 hours?
Anarel [89]
45km/h * 0.5h= 22.5km

The car can travel 22.5km in 0.5 hours
6 0
3 years ago
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A football is kicked from ground level at an angle of 53 degrees. It reaches a maximum height of 7.8 meters before returning to
Nonamiya [84]

Answer:

1.61 second

Explanation:

Angle of projection, θ = 53°

maximum height, H = 7.8 m

Let T be the time taken by the ball to travel into air. It is called time of flight.

Let u be the velocity of projection.

The formula for maximum height is given by

H = \frac{u^{2}Sin^{2}\theta }{2g}

By substituting the values, we get

7.8= \frac{u^{2}Sin^{2}53 }{2\times 9.8}

u = 9.88 m/s

Use the formula for time of flight

T = \frac{2uSin\theta }{g}

T = \frac{2\times 9.88\times Sin53 }{9.8}

T = 1.61 second

7 0
3 years ago
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