Se calcula que la aceleración es - 8,35 m/s.
<h3 /><h3>¿Qué es la aceleración?</h3>
Ahora sabemos lo siguiente de la pregunta;
Velocidad inicial (u) = 60 km/h o 16,7 m/s
Tiempo empleado (t) = 2 s
Dado que;
v = tu + en
v = 0 m/s porque el carro se detenía
tu = -en
a = -(u/t)
a= -1(6,7 m/s/2 s)
a =- 8,35 m/s
La aceleración es negativa porque la velocidad disminuye con el tiempo.
Obtenga más información sobre la aceleración: brainly.com/question/12550364
#SPJ1
(4,4)(-6,4)...notice how ur y coordinates on both of ur points is the same...that means u have a horizontal line with a slope of 0....the equation would be
y = 4.....but in point slope form...not 100% sure
y - y1 = m(x - x1)
slope(m) = 0
using (4,4)...x1 = 4 and y1 = 4
now sub
y - 4 = 0(x - 4) <==
y - y1 = m(x - x1)
slope(m) = 0
using (-6,4)...x1 = -6 and y1 = 4
sub
y - 4 = 0(x - (-6) =
y - 4 = 0(x + 6) <==
Answer:
3/8
Step-by-step explanation:
HHT,THH, and TTH are the 3 outcomes with 1 head out of 8 total outcomes
The common denominater for the question is 35. Multiply 7 x 5 because in this case, they have no number before that which is common.
Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at brainly.com/question/23659342.
#SPJ1
