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kotykmax [81]
2 years ago
15

Ok so how do I make a forehead thermometer say I'm sick

Mathematics
1 answer:
Ivahew [28]2 years ago
5 0

Look down or and try ways to get your face to feel warm, hot, blush.

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In a survey of 300 adults, 10% did not know how to ride a bike. How many people is this? Show your work.
Lyrx [107]

Answer:

30

Step-by-step explanation:

300 * 0.1 = 30

0.1 meaning 10%

4 0
3 years ago
The coordinates of quadrilateral PQRS are P(–3, 0), Q(0, 4), R(4, 1), and S(1, –3). What best describes the quadrilateral?
denis-greek [22]

Answer:

Square

Step-by-step explanation:

Plot the vertices of the quadrilateral PQRS on the coordinate plane (see attached diagram). The diagram shows that this is a square. Let's prove it.

1. Find all sides lengths:

PQ=\sqrt{(-3-0)^2+(0-4)^2}=\sqrt{(-3)^2+(-4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\QR=\sqrt{(0-4)^2+(4-1)^2}=\sqrt{(-4)^2+(3)^2}=\sqrt{16+9}=\sqrt{25}=5\\ \\RS=\sqrt{(4-1)^2+(1-(-3))^2}=\sqrt{(3)^2+(4)^2}=\sqrt{9+16}=\sqrt{25}=5\\ \\SP=\sqrt{(1-(-3))^2+(-3-0)^2}=\sqrt{(4)^2+(-3)^2}=\sqrt{16+9}=\sqrt{25}=5

All sides have the same lengths.

2. Find the slopes of all lines:

PQ:\ \dfrac{4-0}{0-(-3)}=\dfrac{4}{3}\\ \\QR:\ \dfrac{1-4}{4-0}=-\dfrac{3}{4}\\ \\RS:\ \dfrac{-3-1}{1-4}=\dfrac{4}{3}\\ \\SP:\ \dfrac{0-(-3)}{-3-1}=-\dfrac{3}{4}

Since the slopes of PQ and RS are the same, lines PQ and RS are parallel. Since the slopes of QR and SP are the same, lines QR and SP are parallel.

The slopes \frac{4}{3} and -\frac{3}{4} have the product of

-\dfrac{3}{4}\cdot \dfrac{4}{3}=-1,

then lines are pairwise perpendicular.

This means PQRS is a square.

4 0
4 years ago
What is the remainder when x2−4x+2 is divided by x+3?
Airida [17]
2x_45 I’m trying to figure it out but if I can get my text from work then I can go back to my dads house tonight and then I get off
5 0
2 years ago
Read 2 more answers
Solve for x<br>6x²+2x-12​
dem82 [27]

Answer:

Step-by-step explanation:

Solving for x means you have to factor. First factor out the GCF of 2 to get:

2(3x^2+x-6) and now we'll factor using the regular old method of ac and then factoring by grouping. In our polynomial, a = 3, b = 1, c = -6. Therefore, a times c is 3 * -6 which is -18. We need some combinations of the factors of 18 that will add to give us 1, the b term in the middle. The factors of 18 are:

1, 18

2, 9

3, 6 and that's it. Hm...it seems that won't work, so let's throw this into the quadratic formula, going back to the original and a = 6, b = 2 and c = -12:

x=\frac{-2+/-\sqrt{2^2-4(6)(-12)} }{2(6)} and

x=\frac{-2+/-\sqrt{4+288} }{12} and

x=\frac{-2+/-\sqrt{292} }{12} and

x=\frac{-2+/-\sqrt{4*73} }{12} and

x=\frac{-2+/-2\sqrt{73} }{12} which finally simplifies to

x=\frac{-1+/-\sqrt{73} }{6} No wonder that didn't factor using the traditional method of factoring! We could have found that out by finding first the value of the discriminant, but oh well!

8 0
3 years ago
Enter the slope of the line through the points (5, 2) and (-3, -7).
ehidna [41]

Answer:

m=9/8 or 1 1/8

Step-by-step explanation:

m= change in y over change in x

2 - -7 = 9

5 - -3 = 8

3 0
3 years ago
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